Reputation: 503
I'm trying to access a dialog item from a function that is not in the same class as the dialog class. How can I do that?
Example:
class AnotherClass : CClas
{
AnotherClass();
public:
void MyFunction();
};
void AnotherClass::MyFunction() //Message overwriting, can't change parameters
{
CClass* temp = (CClass*)GetDlgItem(IDC_ID); //Reference to dialog item IDC_ID
temp->DoSomething(); //This gives me an assertion error
}
I know I can use "this" if it is the same dialog item than the message, but I want to access another dialog item.
Thanks for your attention.
Solution:
As suggested by Moo-Juice, you can simply pass the dialog when you instantiate the class. In my case, I couldn't do that. For some reason subclassing didn't work that way. If you face the same issue when doing an application in MFC , you can create a pointer to a CDialog and pass it your main dialog at OnInitDialog():
Example (Class):
class AnotherClass : CClass
{
AnotherClass();
public:
void MyFunction();
CDialog * mainDialog;
};
void AnotherClass::MyFunction() //Message overwriting, can't change parameters
{
CClass* temp = (CClass*)mainDialog->GetDlgItem(IDC_ID); //Reference to dialog item IDC_ID
temp->DoSomething(); //This gives me an assertion error
}
Example (OnInitDialog()):
MyMainDialog::OnInitDialog()
{
...
AnotherClass obj; //Instantiate class
obj->mainDialog = this;
return true;
}
In this example simply passing it as a parameter when creating the object makes more sense. It just didn't work with me for what I was doing.
Hope it helps anyone with a similar question.
Upvotes: 2
Views: 6916
Reputation: 38825
When you instantiate AnotherClass
, pass it the dialog class:
class AnotherClass
{
private:
CDialog& dialog_;
public:
AnotherClass(CDialog& dialog) : dialog_(dialog) { }
void MyFunction();
};
void AnotherClass::MyFunction()
{
CClass* temp = (CClass*)dialog_.GetDigItem(IDC_ID);
temp->doSOmething();
}
Upvotes: 3