CODEWITHSUNDEEP
javaandroid
user1082770
user1082770

Reputation: 91

Android Java Voice Recognition only need 1 result.......How to obtain 1 result?

I have a speech recognition program that displays 5-6 results. I only want the 1st result to appear. Can you help with this please?

code:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // TODO Auto-generated method stub


    if (requestCode == check && resultCode == RESULT_OK){
        ArrayList<String> results = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
        lv.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, results));

    }

Please advise?

Thank you. FlinxSYS

Upvotes: 0

Views: 390

Answers (2)

vstm
vstm

Reputation: 12537

There is a flag called RecognizerIntent.EXTRA_MAX_RESULTS. You have to do this before the startActivityForResult-call I guess (from the voice recognition example):

// Specify how many results you want to receive. The results will be sorted
// where the first result is the one with higher confidence.
intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS, 1);

// ...
startActivityForResult(intent,0);

Upvotes: 1

Tudor
Tudor

Reputation: 62459

You could have a flag indicating that a result was already found:

private boolean flag = false;

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // TODO Auto-generated method stub


    if (!flag && requestCode == check && resultCode == RESULT_OK){
        ArrayList<String> results = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
        lv.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, results));
        flag = true;
    }

Once the flag is set to true at the first found result, the if condition will be false for any other execution of the handler.

Upvotes: 0

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