Reputation:
Is there a way to filter a multi-line select box using jQuery?
I'm a new to jQuery and can't seem to figure out the best way to do this.
For example if I have:
<select size="10">
<option>abc</option>
<option>acb</option>
<option>a</option>
<option>bca</option>
<option>bac</option>
<option>cab</option>
<option>cba</option>
...
</select>
I want to filter this list based on a selection drop down with:
<select>
<option value="a">Filter by a</option>
<option value="b">Filter by b</option>
<option value="c">Filter by c</option>
</select>
Upvotes: 4
Views: 585
Reputation: 11056
Something like this might do the trick (assuming you give your 'Filter by...' select an id of filter and the filtered / other select an id of otherOptions):
$(document).ready(function() {
$('#filter').change(function() {
var selectedFilter = $(this).val();
$('#otherOptions option').show().each(function(i) {
var $currentOption = $(this);
if ($currentOption.val().indexOf(selectedFilter) !== 0) {
$currentOption.hide();
}
});
});
});
UPDATE: As @Brian Liang pointed out in the comments, you might have problems setting the <option> tags to display:none. Therefore the following should give you a better cross-browser solution:
$(document).ready(function() {
var allOptions = {};
$('#otherOptions option').each(function(i) {
var $currentOption = $(this);
allOptions[$currentOption.val()] = $currentOption.text();
});
$('#filter').change(function() {
// Reset the filtered select before applying the filter again
setOptions('#otherOptions', allOptions);
var selectedFilter = $(this).val();
var filteredOptions = {};
$('#otherOptions option').each(function(i) {
var $currentOption = $(this);
if ($currentOption.val().indexOf(selectedFilter) === 0) {
filteredOptions[$currentOption.val()] = $currentOption.text();
}
});
setOptions('#otherOptions', filteredOptions);
});
function setOptions(selectId, filteredOptions) {
var $select = $(selectId);
$select.html('');
var options = new Array();
for (var i in filteredOptions) {
options.push('<option value="');
options.push(i);
options.push('">');
options.push(filteredOptions[i]);
options.push('</option>');
}
$select.html(options.join(''));
}
});
Upvotes: 5