CODEWITHSUNDEEP
c#floating-pointnumbers
Marty
Marty

Reputation: 39456

Incrementing decimal numbers in C#

I'm making my way through the beginners tutorials for XNA (C#) and have veered off in my own direction once I learned rendering and positioning, having my own game development experience.

I'm trying to make a property VelocityY on my class Ship. I want to be able to increment this value by values that are decimal, ie:

VelocityY += 0.45;

I figured that float was the type required here, but when I try compile I get this error:

Literal of type double cannot be implicitly converted to type 'float'; use an 'F' suffix to create a literal of this type.

I'm not really sure what the first part means as I haven't made use of double as far as I know. VelocityY is declared like this:

public float VelocityY = 0;

I tried using double and even int instead but I still can't increment by non-whole numbers. Whole numbers work fine.

Upvotes: 2

Views: 6114

Answers (3)

Kishore Kumar
Kishore Kumar

Reputation: 12874

By Default all values you give as 0.45 or .68 are double in C# environment, but here you need to say the compiler that the number you gave was float by adding a suffix F to it.

variable += 0.45F;

Upvotes: 0

Roee Gavirel
Roee Gavirel

Reputation: 19445

you should change

public float VelocityY = 0;
to
public double VelocityY = 0;

or

VelocityY += 0.45;
to
VelocityY += 0.45F;

Upvotes: 1

Jon Skeet
Jon Skeet

Reputation: 1500395

The type of the literal 0.45 is double. If you want to make it a float, use the suffix f or F, like the compiler error says:

VelocityY += 0.45F;

Basically, if you don't specify a suffix for a literal including a decimal point, it's implicitly double. You can use a suffix to make it explicit:

decimal a = 0.45M;
float b = 0.45F;
double c = 0.45D;

Upvotes: 7

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