Reputation:
Sample.csv contains the following:
NAME Id No Dept
Tom 1 12 CS
Hendry 2 35 EC
Bahamas 3 21 IT
Frank 4 61 EE
And the Python file contains the following code:
import csv
ifile = open('sample.csv', "rb")
read = csv.reader(ifile)
for row in read :
print (row)
When I run the above code in Python, I get the following exception:
File "csvformat.py", line 4, in for row in read : _csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)
How can I fix it?
Upvotes: 206
Views: 350172
Reputation: 1
You need to change the open mode to text. I came upon this on the documentation, and this example is not working:
EmployeeRecord = namedtuple('EmployeeRecord', 'name, age, title, department, paygrade')
import csv
for emp in map(EmployeeRecord._make, csv.reader(open("employees.csv", "rb"))):
print(emp.name, emp.title)
Upvotes: 0
Reputation: 153
You can do something like this in django
import csv
import io
csv_file = = open('sample.csv', "rb")
file = csv_file.read().decode('utf-8')
csv_reader = csv.DictReader(io.StringIO(file))
for row in csv_reader:
print(row)
Upvotes: 1
Reputation: 1072
This is a GOTCHA in Django. The open that comes with filefield always opens the file in byte mode as far as I can tell. You need to open with Python's open instead.
So with avccont_datafile being an instance of a model with a field called datafile = django.db.models.FileField(), The following code....
with avccount_datafile.datafile.file.open('rt') as fp:
self.avc_data = csv.DictReader(fp)
gives the error
_csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)
but this fixes it
filename = avccount_datafile.datafile.file.name
with open(filename, 'rt') as fp:
self.avc_data = csv.DictReader(fp)
Upvotes: 3
Reputation: 1211
The reason it is throwing that exception is because you have the argument rb
, which opens the file in binary mode. Change that to r
, which will by default open the file in text mode.
Your code:
import csv
ifile = open('sample.csv', "rb")
read = csv.reader(ifile)
for row in read :
print (row)
New code:
import csv
ifile = open('sample.csv', "r")
read = csv.reader(ifile)
for row in read :
print (row)
Upvotes: 121
Reputation: 5573
In Python3, csv.reader
expects, that passed iterable returns strings, not bytes. Here is one more solution to this problem, that uses codecs
module:
import csv
import codecs
ifile = open('sample.csv', "rb")
read = csv.reader(codecs.iterdecode(ifile, 'utf-8'))
for row in read :
print (row)
Upvotes: 50
Reputation: 1336
I had this error when running an old python script developped with Python 2.6.4
When updating to 3.6.2, I had to remove all 'rb' parameters from open calls in order to fix this csv reading error.
Upvotes: 11
Reputation: 395045
Your problem is you have the b
in the open
flag.
The flag rt
(read, text) is the default, so, using the context manager, simply do this:
with open('sample.csv') as ifile:
read = csv.reader(ifile)
for row in read:
print (row)
The context manager means you don't need generic error handling (without which you may get stuck with the file open, especially in an interpreter), because it will automatically close the file on an error, or on exiting the context.
The above is the same as:
with open('sample.csv', 'r') as ifile:
...
or
with open('sample.csv', 'rt') as ifile:
...
Upvotes: 33
Reputation: 172249
You open the file in text mode.
More specifically:
ifile = open('sample.csv', "rt", encoding=<theencodingofthefile>)
Good guesses for encoding is "ascii" and "utf8". You can also leave the encoding off, and it will use the system default encoding, which tends to be UTF8, but may be something else.
Upvotes: 251