CODEWITHSUNDEEP
jqueryajaxasp.net-mvcjson
Snake Eyes
Snake Eyes

Reputation: 16764

Send JSON data via POST (ajax) and receive json response from Controller (MVC)

I created a function in javascript like that:

function addNewManufacturer() {
    var name = $("#id-manuf-name").val();
    var address = $("#id-manuf-address").val();
    var phone = $("#id-manuf-phone").val();
    
    var sendInfo = {
        Name: name,
        Address: address,
        Phone: phone
    };
    
    $.ajax({
        type: "POST",
        url: "/Home/Add",
        dataType: "json",
        success: function (msg) {
            if (msg) {
                alert("Somebody" + name + " was added in list !");
                location.reload(true);
            } else {
                alert("Cannot add to list !");
            }
        },
        data: sendInfo
    });
}

I called jquery.json-2.3.min.js script file and I used it for toJSON(array) method.

In controller, I have this Add action

[HttpPost]
public ActionResult Add(PersonSheets sendInfo) {
    bool success = _addSomethingInList.AddNewSomething( sendInfo );

    return this.Json( new {
         msg = success
    });
      
}

But sendInfo as method parameter becomes null.

The model:

public struct PersonSheets
{
    public int Id;
    public string Name;
    public string Address;
    public string Phone;
}

public class PersonModel
{
    private List<PersonSheets> _list;
    public PersonModel() {
         _list= GetFakeData();
    }

    public bool AddNewSomething(PersonSheets info) {
         if ( (info as object) == null ) {
            throw new ArgumentException( "Person list cannot be empty", "info" );
         }

         PersonSheets item= new PersonSheets();
         item.Id = GetMaximumIdValueFromList( _list) + 1;
         item.Name = info.Name;
         item.Address = info.Address;
         item.Phone = info.Phone;
             
         _list.Add(item);

         return true;
    }
}

How could I do in action method when the data was sent with POST ?

I don't know how to use. Also, it is possible to send back the response (to ajax) via JSON ?

Upvotes: 178

Views: 1079603

Answers (8)

Bashir Onuche Okala III
Bashir Onuche Okala III

Reputation: 38

    const URL = "http://localhost:8779/api/v1/account/create";
    let reqObj = {accountName:"", phoneNo:""}

    const httpRequest = new XMLHttpRequest();
    let accountName = document.getElementById("accountName").value
    let phoneNo = document.getElementById("phoneNo").value
    reqObj.accountName = accountName;
    reqObj.phoneNo = phoneNo;
    console.log(reqObj);
    console.log(JSON.stringify(reqObj))
    httpRequest.onload = function() {
        document.getElementById("mylabel").innerHTML = this.responseText;
    }
    httpRequest.open("POST", URL);
    httpRequest.overrideMimeType("application/json");
    httpRequest.send(reqObj);

Upvotes: 0

Sivakumar D
Sivakumar D

Reputation: 109

Need to use JSON.stringify
And in the Flask use json.loads

res = request.get_data("data")
d_token = json.loads(res)

json.loads returns a dictionary, te values can be retrieved d_token['tokenID']

 $.ajax({
            type: "POST",
            url: "/subscribe",
            contentType: 'application/json;charset=UTF-8',
            data: JSON.stringify({'tokenID':  token}),
            success: function (data) {
                console.log(data);
              
            }
     });

Flask

@app.route('/test', methods=['GET', 'POST'])
def test():
    res = request.get_data("data")
    d_token = json.loads(res)
    logging.info("Test called..{}".format(d_token["tokenID"]))

Upvotes: 1

user1799669
user1799669

Reputation: 131

To post JSON, you will need to stringify it. JSON.stringify and set the processData option to false.

$.ajax({
    url: url,
    type: "POST",
    data: JSON.stringify(data),
    processData: false,
    contentType: "application/json; charset=UTF-8",
    complete: callback
});

Upvotes: 11

Praveen Prasad
Praveen Prasad

Reputation: 32137

Create a model

public class Person
{
    public string Name { get; set; }
    public string Address { get; set; }
    public string Phone { get; set; }
}

Controllers Like Below

    public ActionResult PersonTest()
    {
        return View();
    }

    [HttpPost]
    public ActionResult PersonSubmit(Vh.Web.Models.Person person)
    {
        System.Threading.Thread.Sleep(2000);  /*simulating slow connection*/

        /*Do something with object person*/


        return Json(new {msg="Successfully added "+person.Name });
    }

Javascript

<script type="text/javascript">
    function send() {
        var person = {
            name: $("#id-name").val(),
            address:$("#id-address").val(),
            phone:$("#id-phone").val()
        }

        $('#target').html('sending..');

        $.ajax({
            url: '/test/PersonSubmit',
            type: 'post',
            dataType: 'json',
            contentType: 'application/json',
            success: function (data) {
                $('#target').html(data.msg);
            },
            data: JSON.stringify(person)
        });
    }
</script>

Upvotes: 150

Kirsten
Kirsten

Reputation: 500

Your PersonSheets has a property int Id, Id isn't in the post, so modelbinding fails. Make Id nullable (int?) or send atleast Id = 0 with the POst .

Upvotes: 0

Neha
Neha

Reputation: 2965

var SendInfo= { SendInfo: [... your elements ...]};

        $.ajax({
            type: 'post',
            url: 'Your-URI',
            data: JSON.stringify(SendInfo),
            contentType: "application/json; charset=utf-8",
            traditional: true,
            success: function (data) {
                ...
            }
        });

and in action 

public ActionResult AddDomain(IEnumerable<PersonSheets> SendInfo){
...

you can bind your array like this

var SendInfo = [];

$(this).parents('table').find('input:checked').each(function () {
    var domain = {
        name: $("#id-manuf-name").val(),
        address: $("#id-manuf-address").val(),
        phone: $("#id-manuf-phone").val(),
    }

    SendInfo.push(domain);
});

hope this can help you.

Upvotes: 167

Hiep Nguyen
Hiep Nguyen

Reputation: 161

Use JSON.stringify(<data>).

Change your code: data: sendInfo to data: JSON.stringify(sendInfo). Hope this can help you.

Upvotes: 15

Abdul Munim
Abdul Munim

Reputation: 19217

You don't need to call $.toJSON and add traditional = true

data: { sendInfo: array },
traditional: true

would do.

Upvotes: -2

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