Michael D. Irizarry
Michael D. Irizarry

Reputation: 6302

C# Regex match anything inside Parentheses

I want to match anything inside parentheses but the result must exclude the parentheses as well.

Examples:
Initialize(P90W)
Brake(45X)

Result:
990W
45X

note results without the Parentheses.

I've been trying to make this work but to no avail I tried a few variations but I know it's a simple thing I'm missing and I don't want to go using Replace to achieve it.

var item = "Brake(45X)"
Regex searchTerm = new Regex(@"\((.*)\)");
var value = (searchTerm.Match(item).Groups.Count > 0) ?
    searchTerm.Match(item).Groups[0].Value : string.Empty;

Upvotes: 20

Views: 38321

Answers (5)

oguzh4n
oguzh4n

Reputation: 682

try this:

var pattern = @".*public.*(.*\(.*\))";
Regex.Matches(input,pattern)

Upvotes: 0

Savas Vedova
Savas Vedova

Reputation: 5692

Remove the inner paranthesis and try again:

new Regex(@"(\([^\)]+\))");

When you do not escape paranthesis in regex, if you are using group match it will only return the content within the paranthesis. So if you have, new Regex(@'(a)(b))', match 1 will be a and match 2 will be b. Match 0 is the entire match.

Upvotes: 3

FailedDev
FailedDev

Reputation: 26930

Some people accuse me of using zero width assertions all the time:

resultString = Regex.Match(subjectString, @"(?<=\().+?(?=\))").Value;

But they do exactly what you want. Don't capture what you don't want to capture.

Upvotes: 42

Matthew
Matthew

Reputation: 25763

try regex @"\((.*?)\)"

EDIT: Also the result will be group 1 not 0, group 0 should contain the entire regex result, not the first parenthesized value

Upvotes: 12

kol
kol

Reputation: 28688

Regex searchTerm = new Regex(@"\(([^\)]*)\)");

Upvotes: 0

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