Reputation: 7103
I'm trying to use just the IP address (inet) as a parameter in a script I wrote.
Is there an easy way in a unix terminal to get just the IP address, rather than looking through ifconfig
?
Upvotes: 197
Views: 353975
Reputation: 31746
Generally, it is never guaranteed that a system will only have one IP address, for example, you can have both an ethernet and wlan connections, and if you have active VPN connections then you'll have yet more IP addresses.
On Linux, hostname -I
will list the current IP address(es). Relying on it always returning just one IP address will most likely not work as expected under some scenarios, so a more reliable way would be converting the result to an array and then loop over the elements:
ips=($(hostname -I))
for ip in "${ips[@]}"
do
echo $ip
done
Note: If
hostname -I
returns the IP both in IPv4 and IPv6 formats then you can use insteadhostname -I | cut -f1 -d' '
to only show the IPv4 IP.
On OSX, if you know the interface, you could use:
~$ ipconfig getifaddr en0
# OUTPUT: 192.168.1.123
which will return just the IP address.
To detect dynamically the (first) active network interface on MacOS:
network_device=$(scutil --dns |awk -F'[()]' '$1~/if_index/ {print $2;exit;}')
ip=$(ipconfig getifaddr "$network_device")
echo $ip
### OUTPUT: 192.168.1.123
To get the external IP you could query a text-mode service, for example curl https://ipecho.net/plain
would return a plain text external IP.
A supposedly faster approach could be to query a known DNS server, e.g.:
dig @ns1-1.akamaitech.net ANY whoami.akamai.net +short
Upvotes: 70
Reputation: 377
This is universal command which is worked for most of the linux flavors.
This command shows details about your IPv4 address which is configured on Linux system.
ip -4 addr show scope global | grep inet | tr -s " " | awk '{print $NF,$2}'
ip -4 addr show scope global | grep inet | tr -s " " | awk '{print $NF,$2}' | paste -sd ','
Upvotes: 0
Reputation: 11
result only IPv4 address exclude local specific addresses: 10.x.x.x
, 127.x.x.x
, 172.x.x.x
, 192.x.x.x
:
ip -4 addr | grep -oP '(?<=inet\s)\d+(\.\d+){3}' | grep -vE '^10|^127|^172|^192'
Upvotes: 0
Reputation: 420
On Ubuntu( and Debian like distro)
To obtain just the local address digits, execute the following command:
hostname -I | awk '{print $1}'
For a comprehensive picture of your network interface configuration and global IP address use:
curl -4 icanhazip.com
curl ifconfig.co //this responds faster
To dive deeper into the mysteries of any IP address (including your own):
whois $(curl ifconfig.co)
Ensure you have the whois
tool installed. If not, simply execute:
sudo apt-get install whois
Upvotes: 5
Reputation: 708
hostname -I
This command will give you the exact IP address as you want in Ubuntu. Note the flag is uppercase.
Upvotes: 29
Reputation: 437
yet another way to do it.
I often need to check the IP of various interfaces (e.g eth0, tunnel, etc.)
So this is how i do it:
ip -4 -br a | awk '{print $1,$3}'
output:
$ ip -4 -br a | awk '{print $1,$3}'
lo 127.0.0.1/8
eth0 192.168.0.248/24
tun0 192.168.119.1
If you do not care about the network adapter, just remove the $1 from awk command.
ip -4 -br a | awk '{print $3}'
127.0.0.1/8
192.168.0.248/24
192.168.119.124/24
to make it easy, i just add it as an alias (remember to escape the $'s!)
$ alias me="ip -4 -br a | awk '{print \$1,\$3}'"
$ me
lo 127.0.0.1/8
eth0 192.168.0.248/24
tun0 192.168.119.124/24
Upvotes: 2
Reputation: 7227
ip -4 addr show eth0
doesn't work on some machines. For example, I get this error:
ip: symbol lookup error: ip: undefined symbol: bpf_program__section_name, version LIBBPF_0.2.0
This works for me:
/sbin/ifconfig eth0 | grep 'inet ' | awk '{ print $2}'
This has one less pipe than the accepted answer. In addition, my ifconfig output does not have inet addr
.
To get the IPv6 address, use this:
/sbin/ifconfig eth0 | grep 'inet6 ' | awk '{ print $2}'
Upvotes: 8
Reputation: 888
If you mean "Linux" and portable to Embedded Linux OS:
ip route get 8.8.8.8 | head -n 1 | tr -s ' ' | cut -d ' ' -f 7
This eliminates the need to call awk, which is not installed on all embedded Linux. Awk is a bit heavy of a process just to get a field from a string.
Every Linux environment will provide tr, head, and cut. If the embedded environment is really old it may have 'ifconfig' only, but you get the picture here: get the line, remove padding, cut what you need.
Upvotes: 0
Reputation: 51
ip adddr, the short way
ip -4 -br addr show enp1s0 | awk -F" " '{print $3}'|cut -d'/' -f1
or shorten
ip -4 -br a s enp1s0 | awk -F" " '{print $3}'|cut -d'/' -f1
must work in most modern Linux distribution
Upvotes: 5
Reputation: 122
the easiest way is as Mikko said
hostname --all-ip-addresses
you can also do that for little more details :
ip route
Upvotes: 3
Reputation: 16015
The IPv4 address for the default route:
ip address show $(ip route | grep "^default " | head -n1 | grep -Po "(?<=dev )[^ ]+") | grep -Po "(?<=inet )[^ /]+"
The IPv6 address for the default route:
ip address show $(ip route | grep "^default " | head -n1 | grep -Po "(?<=dev )[^ ]+") | grep -Po "(?<=inet6 )[^ /]+"
These only require commands ip
and grep
with support for -P
and -o
. The head -1
is required because ip route
may show multiple default routes when system has complex enough network setup.
If you don't mind which IP is which, you can just do
ip route | grep -Po '(?<=src )[^ ]+'
or
hostname --all-ip-addresses
Upvotes: 3
Reputation: 1771
If you don't want to use ifconfig
nor regex...
ip addr | grep eth0 | grep inet | awk '{print $2}' | cut -d"/" -f1
Upvotes: 0
Reputation:
I don't see any answer with nmcli
yet which is a command-line tool for controlling NetworkManager.
So here you go :)
wolf@linux:~$ nmcli device
DEVICE TYPE STATE CONNECTION
eth1 ethernet unavailable --
eth0 ethernet unmanaged --
lo loopback unmanaged --
wolf@linux:~$
If you want to get the information from specific network interface (let say lo
for this example)
wolf@linux:~$ nmcli device show lo
GENERAL.DEVICE: lo
GENERAL.TYPE: loopback
GENERAL.HWADDR: 00:00:00:00:00:00
GENERAL.MTU: 65536
GENERAL.STATE: 10 (unmanaged)
GENERAL.CONNECTION: --
GENERAL.CON-PATH: --
IP4.ADDRESS[1]: 127.0.0.1/8
IP4.GATEWAY: --
IP4.ROUTE[1]: dst = 127.0.0.0/8, nh = 0.0.0.0,>
IP4.ROUTE[2]: dst = 127.0.0.1/32, nh = 0.0.0.0>
IP6.ADDRESS[1]: ::1/128
IP6.GATEWAY: --
IP6.ROUTE[1]: dst = ::1/128, nh = ::, mt = 256
IP6.ROUTE[2]: dst = ::1/128, nh = ::, mt = 0, >
wolf@linux:~$
But since you just want to get the IP address, just send the output to grep
, cut
or awk
.
Let's do it step by step. (Not sure what's wrong, the code sample format just didn't work for these 3 example.)
Get the IPv4 line
wolf@linux:~$ nmcli device show lo | grep 4.A IP4.ADDRESS[1]: 127.0.0.1/8 wolf@linux:~$
Use awk
to get the IP
wolf@linux:~$ nmcli device show lo | awk '/4.A/ {print $2}' 127.0.0.1/8 wolf@linux:~$
Use cut
to remove the CIDR notation (/8)
wolf@linux:~$ nmcli device show lo | awk '/4.A/ {print $2}' | cut -d / -f1 127.0.0.1 wolf@linux:~$
There your answer.
Please take note that there are tons of ways to do it using the tools that I demonstrated just now.
Let's recap the commands that I used.
nmcli device show lo | grep 4.A
nmcli device show lo | awk '/4.A/ {print $2}'
nmcli device show lo | awk '/4.A/ {print $2}' | cut -d / -f1
Sample output for these 3 commands
Command 1 output
IP4.ADDRESS[1]: 127.0.0.1/8
Command 2 output
127.0.0.1/8
Command 3 output
127.0.0.1
Upvotes: 1
Reputation: 4514
To print only the IP address of eth0
, without other text:
ifconfig eth0 | grep -Po '(?<=inet addr:)[\d.]+'
To determine your primary interface (because it might not be "eth0"), use:
route | grep ^default | sed "s/.* //"
The above two lines can be combined into a single command like this:
ifconfig `route | grep ^default | sed "s/.* //"` \
| grep -Po '(?<=inet addr:)[\d.]+'
Upvotes: 5
Reputation: 1
These two ways worked for me:
To get IP address of your interface eth0. Replace eth0 in the below example with your interface name.
ifconfig eth0 | grep -w "inet" | tr -s " " | cut -f3 -d" "
Using hostname: This will give you the inet i.e. IPAddress of your etho. using -I will give you inet value of all the interfaces whereever this value is present.
hostname -i
Upvotes: 0
Reputation: 1441
I prefer not to use awk
and such in scripts.. ip
has the option to output in JSON.
If you leave out $interface
then you get all of the ip addresses:
ip -json addr show $interface | \
jq -r '.[] | .addr_info[] | select(.family == "inet") | .local'
Upvotes: 15
Reputation: 11577
Few answers appear to be using the newer ip
command (replacement for ifconfig
) so here is one that uses ip addr
, grep
, and awk
to simply print the IPv4 address associated with the wlan0
interface:
ip addr show wlan0|grep inet|grep -v inet6|awk '{print $2}'|awk '{split($0,a,"/"); print a[1]}'
While not the most compact or fancy solution, it is (arguably) easy to understand (see explanation below) and modify for other purposes, such as getting the last 3 octets of the MAC address like this:
ip addr show wlan0|grep link/ether|awk '{print $2}'|awk '{split($0,mac,":"); print mac[4] mac[5] mac[6]}'
Explanation: ip addr show wlan0
outputs information associated with the network interface named wlan0
, which should be similar to this:
4: wlan0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP group default qlen 1000
link/ether dc:a6:32:04:06:ab brd ff:ff:ff:ff:ff:ff
inet 172.18.18.1/24 brd 172.18.18.255 scope global noprefixroute wlan0
valid_lft forever preferred_lft forever
inet6 fe80::d340:5e4b:78e0:90f/64 scope link
valid_lft forever preferred_lft forever
Next grep inet
filters out the lines that don't contain "inet" (IPv4 and IPv6 configuration) and grep -v inet6
filters out the remaining lines that do contain "inet6", which should result in a single line like this one:
inet 172.18.18.1/24 brd 172.18.18.255 scope global noprefixroute wlan0
Finally, the first awk
extract the "172.18.18.1/24" field and the second removes the network mask shorthand, leaving just the IPv4 address.
Also, I think it's worth mentioning that if you are scripting then there are often many richer and/or more robust tools for obtaining this information, which you might want to use instead. For example, if using Node.js there is ipaddr-linux
, if using Ruby there is linux-ip-parser
, etc.
See also https://unix.stackexchange.com/questions/119269/how-to-get-ip-address-using-shell-script
Upvotes: 5
Reputation: 3120
When looking up your external IP address on a NATed host, quite a few answers suggest using HTTP based methods like ifconfig.me
eg:
$ curl ifconfig.me/ip
Over the years I have seen many of these sites come and go, I find this DNS based method more robust:
$ dig +short myip.opendns.com @resolver1.opendns.com
I have this handy alias in my ~/.bashrc
:
alias wip='dig +short myip.opendns.com @resolver1.opendns.com'
Upvotes: 0
Reputation: 1
#!/bin/sh
# Tested on Ubuntu 18.04 and Alpine Linux
# List IPS of following network interfaces:
# virtual host interfaces
# PCI interfaces
# USB interfaces
# ACPI interfaces
# ETH interfaces
for NETWORK_INTERFACE in $(ls /sys/class/net -al | grep -iE "(/eth[0-9]+$|vif|pci|acpi|usb)" | sed -E "s@.* ([^ ]*) ->.*@\1@"); do
IPV4_ADDRESSES=$(ifconfig $NETWORK_INTERFACE | grep -iE '(inet addr[: ]+|inet[: ]+)' | sed -E "s@\s*(inet addr[: ]+|inet[: ]+)([^ ]*) .*@\2@")
IPV6_ADDRESSES=$(ifconfig $NETWORK_INTERFACE | grep -iE '(inet6 addr[: ]+|inet6[: ]+)' | sed -E "s@\s*(inet6 addr[: ]+|inet6[: ]+)([^ ]*) .*@\2@")
if [ -n "$IPV4_ADDRESSES" ] || [ -n "$IPV6_ADDRESSES" ]; then
echo "NETWORK INTERFACE=$NETWORK_INTERFACE"
for IPV4_ADDRESS in $IPV4_ADDRESSES; do
echo "IPV4=$IPV4_ADDRESS"
done
for IPV6_ADDRESS in $IPV6_ADDRESSES; do
echo "IPV6=$IPV6_ADDRESS"
done
fi
done
Upvotes: 0
Reputation: 1576
We can simply use only 2 commands ( ifconfig + awk ) to get just the IP (v4) we want like so:
On Linux, assuming to get IP address from eth0
interface, run the following command:
/sbin/ifconfig eth0 | awk '/inet addr/{print substr($2,6)}'
On OSX, assumming to get IP adddress from en0
interface, run the following command:
/sbin/ifconfig en0 | awk '/inet /{print $2}'
To know our public/external IP, add this function in ~/.bashrc
whatismyip () {
curl -s "http://api.duckduckgo.com/?q=ip&format=json" | jq '.Answer' | grep --color=auto -oE "\b([0-9]{1,3}\.){3}[0-9]{1,3}\b"
}
Then run, whatismyip
Upvotes: 4
Reputation: 288
To get only the IP address on Mac OS X you can type the following command:
ipconfig getifaddr en0
Upvotes: 16
Reputation: 87
curl ifconfig.co
This returns only the ip address of your system.
Upvotes: -2
Reputation: 21
You can also use the following command:
ip route | grep src
NOTE: This will only work if you have connectivity to the internet.
Upvotes: 2
Reputation: 31
In man hostname
there is even more easier way which automatically excluding loopback IP and showing only space separated list of all assigned to host ip addresses:
root@srv:~# hostname --all-ip-addresses
11.12.13.14 192.168.15.19
root@srv:~# ip a
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue state UNKNOWN
link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
inet 127.0.0.1/8 scope host lo
inet6 ::1/128 scope host
valid_lft forever preferred_lft forever
2: venet0: <BROADCAST,POINTOPOINT,NOARP,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN
link/void
inet 11.12.13.14/32 scope global venet0:0
inet 192.168.15.19/32 scope global venet0:1
Upvotes: 3
Reputation: 10022
Command ifconfig
is deprected and you should use ip
command on Linux.
Also ip a
will give you scope on the same line as IP so it's easier to use.
This command will show you your global (external) IP:
ip a | grep "scope global" | grep -Po '(?<=inet )[\d.]+'
All IPv4 (also 127.0.0.1):
ip a | grep "scope" | grep -Po '(?<=inet )[\d.]+'
All IPv6 (also ::1):
ip a | grep "scope" | grep -Po '(?<=inet6 )[\da-z:]+'
Upvotes: 6
Reputation: 5168
That would do the trick in a Mac :
ping $(ifconfig en0 | awk '$1 == "inet" {print $2}')
That resolved to ping 192.168.1.2
in my machine.
Pro tip: $(...)
means run whatever is inside the parentheses in a subshell and return that as the value.
Upvotes: 4
Reputation: 380
If you have limited environment, you may use this command:
ip -4 addr show dev eth0 | grep inet | tr -s " " | cut -d" " -f3 | head -n 1
Upvotes: 10
Reputation: 4118
On Redhat 64bit, this solved problem for me.
ifconfig $1|sed -n 2p|awk '{ print $2 }'|awk -F : '{ print $2 }'
Upvotes: 0
Reputation: 297
use this one line script:
ifconfig | grep "inet " | grep -v 127.0.0.1|awk 'match($0, /([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+)/) {print substr($0,RSTART,RLENGTH)}'
mac & linux (tested in ubuntu) both works.
Upvotes: 2
Reputation: 304
I wanted something simple that worked as a Bash alias. I found that hostname -I
works best for me (hostname v3.15). hostname -i
returns the loopback IP, for some reason, but hostname -I
gives me the correct IP for wlan0, and without having to pipe output through grep or awk. A drawback is that hostname -I
will output all IPs, if you have more than one.
Upvotes: 5