CODEWITHSUNDEEP
c++stringstlmaps
Roland Sams
Roland Sams

Reputation: 173

STL Map throwing an error upon search attempt

I am trying to create a map full of strings as keys and integers as values. The problem begins when I try and search with it. Can someone tell me where I went wrong? Is it that I have two Maps in the same statement?

    invale is "ale"
    roomno = 2;
    // roomlist is a map
    // rinventory is another map

    if( roomlist[roomno].rinventory.find( invale ) != map<string, int>::end());

The error I get follows. What overloaded function? It really is a lengthy error.

error C2668: 'std::_Tree<_Traits>::end' : ambiguous call to overloaded function
1>        with
1>        [
1>            _Traits=std::_Tmap_traits<std::string,int,std::less<std::string>,std::allocator<std::pair<const std::string,int>>,false>
1>        ]
1>        c:\program files\microsoft visual studio 9.0\vc\include\xtree(569): could be 'std::_Tree<_Traits>::const_iterator std::_Tree<_Traits>::end(void) const'
1>        with
1>        [
1>            _Traits=std::_Tmap_traits<std::string,int,std::less<std::string>,std::allocator<std::pair<const std::string,int>>,false>
1>        ]
1>        c:\program files\microsoft visual studio 9.0\vc\include\xtree(564): or       'std::_Tree<_Traits>::iterator std::_Tree<_Traits>::end(void)'
1>        with
1>        [
1>            _Traits=std::_Tmap_traits<std::string,int,std::less<std::string>,std::allocator<std::pair<const std::string,int>>,false>
1>        ]
1>        while trying to match the argument list '(void)'

Thank you in advance.

Upvotes: 1

Views: 325

Answers (3)

Retired Ninja
Retired Ninja

Reputation: 4924

It should be

if( roomlist[roomno].rinventory.find( invale ) != roomlist[roomno].rinventory.end());

Upvotes: 0

Igor
Igor

Reputation: 27250

Try changing it to:

if( roomlist[roomno].rinventory.find( invale ) != roomlist[roomno].rinventory.end());

Upvotes: 3

BЈовић
BЈовић

Reputation: 64223

map::end() method is not static.

The proper way is like this :

map<string, int>::iterator it = roomlist[roomno].rinventory.find( invale );
if( it != roomlist[roomno].rinventory.end())
  // do stuff

Upvotes: 0

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