CODEWITHSUNDEEP
phpdatetime
A. Rehman Javed
A. Rehman Javed

Reputation: 309

Php date function result is incorrect

Problem with Date function

output: 00:00am on Sunday December 17th, 2011

Problem hour and minutes always display 00:00 and sometime Year is also incorrect

Input date('Y-m-d H:i:s', time());

functions

public function perfect_date_format($date) {
    $dated = str_replace(array(" ", ":"), "-", $date);
    list($year, $month, $day, $hour, $minute) = explode("-", $date);
    $niceday = @date("H:ia \o\\n\ l, F jS, Y", mktime($hour, $minute, 0, $month, $day, $year));
    return $niceday;
  }

Upvotes: 1

Views: 268

Answers (2)

Asaph
Asaph

Reputation: 162771

You have a typo. The 2nd argument to explode() should be $dated, rather than $date. If you do this, the time is correctly displayed.

<?php
function perfect_date_format($date) {
    $dated = str_replace(array(" ", ":"), "-", $date);
    list($year, $month, $day, $hour, $minute) = explode("-", $dated);
    $niceday = @date("H:ia \o\\n\ l, F jS, Y", mktime($hour, $minute, 0, $month, $day, $year));
    return $niceday;
}

echo perfect_date_format('2011-12-17 03:45:00') . "\n";
?>

This outputs:

03:45am on Saturday, December 17th, 2011

BTW: It's safe to remove the error suppressor operator (ie. @) in the code above. It was simply suppressing errors or warnings caused by the bug identified above. Now that the bug is fixed, the @ isn't doing anything.

Upvotes: 3

Josh
Josh

Reputation: 11070

It's very difficult to know hot to correct your code without knowing what you're passing to perfect_date_format, but I'll make a wild guess and assume that strtotime understands how to parse your $date:

public function perfect_date_format($date) {
    $time = strtotime($date);
    return date("H:ia \o\\n\ l, F jS, Y", $time);
}

If that doesn't work, then please provide the format of the data you're passing as $date.

Upvotes: 1

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