CODEWITHSUNDEEP
javaandroid
Nikunj Patel
Nikunj Patel

Reputation: 22076

Base64 decode Stuck

i need to convert a base64 value into string array so simply i have write this : 

String s[] = new String[partyname.length];
        for(int i=0;i<=partyname.length;i++)
        {
        byte[] bytes = Base64.decode(partyname[i], Base64.DEFAULT);
                String string = new String(bytes, "UTF-8");
                s[i] = string;
                System.out.println("string is ::" + string+s[i]);


        }

but i dont know why it raise null pointer error at s[i] = string; line if i remove it then working fine so please help me out.

Upvotes: 0

Views: 484

Answers (3)

Simone-Cu
Simone-Cu

Reputation: 1129

As said, s is null, I want to add another consideration:
The for loop should be: for(int i=0;i<partyname.length;i++) instead of for(int i=0;i<=partyname.length;i++)

Upvotes: 1

Roger Lindsj&#246;
Roger Lindsj&#246;

Reputation: 11553

You need to create your String array that s references first. You have

String[] s = null;

So when you try to use s such as 

s[i] = string;

Then there s is still null, and trying to get the i element of s gives you the null pointer.

From the rest of the code I think you want a String array with the same number of elements as party name, so you need

String[] s = new String[partyname.length];

Upvotes: 1

Oliver Charlesworth
Oliver Charlesworth

Reputation: 272687

Because s is null.

You probably want this as the first line:

String[] s = new String[partyname.length];

Upvotes: 6

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