Reputation: 187
I want to use Maven to create two separate jars for my project.
One that will include everything under the **/client
package and one that will include everything under the **/server
package. The client package should also contain the sources.
Question 1: How can I setup my pom to produce these two separate jars?
Question 2: Is it possible to create both with a single maven command?
Any help is appreciated.
Thank you very much!
Upvotes: 2
Views: 4580
Reputation: 187
After hours of searching, researching, banging my head against the desk, bleeding, and crying, I have solved this by using Maven's assembly plug-in.
Here is how it goes:
I created two separate assembly descriptors. Firstly, ${basedir}/src/main/assembly/client.xml
(src/main/assembly
is apparently the standard place for Maven assembly descriptors)
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>client</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.build.directory}/classes</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>**/client/**</include>
</includes>
</fileSet>
<fileSet>
<directory>${project.basedir}/src/main/java</directory>
<outputDirectory>/</outputDirectory>
<useDefaultExcludes>false</useDefaultExcludes>
<includes>
<include>**/client/**</include>
</includes>
</fileSet>
</fileSets>
</assembly>
then ${basedir}/src/main/assembly/server.xml
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>server</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.build.directory}/classes</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>**/server/**</include>
</includes>
</fileSet>
</fileSets>
</assembly>
and added the following to my pom.xml
:
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2.2</version>
<configuration>
<descriptors>
<descriptor>src/main/assembly/client.xml</descriptor>
<descriptor>src/main/assembly/server.xml</descriptor>
</descriptors>
</configuration>
<executions>
<execution>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
run mvn package
... aaand voila!!! One command... two JARs!... so easy that I want to cry for all the time I spent trying to find the solution.
[INFO] --- maven-assembly-plugin:2.2.2:single (default) @ [my project] ---
[INFO] Reading assembly descriptor: src/main/assembly/client.xml
[INFO] Reading assembly descriptor: src/main/assembly/server.xml
[INFO] Building jar: [my project]-1.0-SNAPSHOT-client.jar
[INFO] Building jar: [my project]-1.0-SNAPSHOT-server.jar
[INFO] ------------------------------------------------------------------------
[INFO] BUILD SUCCESS
[INFO] ------------------------------------------------------------------------
[INFO] Total time: 8.202s
[INFO] Finished at: Mon Dec 19 23:43:52 EET 2011
[INFO] Final Memory: 26M/245M
[INFO] ------------------------------------------------------------------------
Upvotes: 0
Reputation: 33789
My advice would be to refactor the projects into a separate client and a separate server project respectively. By adding a multi mudule (scroll down) project that contains both projects, it is possible to build the client and the server in one command.
Upvotes: 8
Reputation: 5032
You would want to use profiles to achieve this. Please see http://maven.apache.org/guides/mini/guide-building-for-different-environments.html
I am not sure if you can package both with a single command easily.
Upvotes: 0