Reputation: 20183
I need to split a JavaScript array into n
sized chunks.
E.g.: Given this array
["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"]
and a n
equals to 4, the output should be this:
[ ["a1", "a2", "a3", "a4"],
["a5", "a6", "a7", "a8"],
["a9", "a10", "a11", "a12"],
["a13"]
]
I aware of pure JavaScript solutions for this problem, but since I am already using Lodash I am wondering if Lodash provides a better solution for this.
I created a jsPerf test to check how much slower the underscore solution is.
Upvotes: 106
Views: 96205
Reputation: 145
Underscore supports _.chunk() natively as of version 1.9.0.
const data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
const chunks = _.chunk(data, 4);
console.log(chunks);
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.9.1/underscore.js"></script>
Upvotes: 7
Reputation: 1388
A possibly simpler expression:
const coll = [ "a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9" ];
const n = 2;
const chunks = _.range(coll.length / n).map(i => coll.slice(i * n, (i + 1) * n));
console.log(chunks);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>
Upvotes: 6
Reputation: 3481
Take a look at lodash' chunk: https://lodash.com/docs#chunk
const data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
const chunks = _.chunk(data, 3);
console.log(chunks);
// [
// ["a1", "a2", "a3"],
// ["a4", "a5", "a6"],
// ["a7", "a8", "a9"],
// ["a10", "a11", "a12"],
// ["a13"]
// ]
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>
Upvotes: 169
Reputation: 131
try this one it is much more practical (for example, if you would want to split the array based on amount of items to be container in each sub array):
function chunk(arr, start, amount){
var result = [],
i,
start = start || 0,
amount = amount || 500,
len = arr.length;
do {
//console.log('appending ', start, '-', start + amount, 'of ', len, '.');
result.push(arr.slice(start, start+amount));
start += amount;
} while (start< len);
return result;
};
and the use in your case:
var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17],
chunked = chunk(arr, 0, Math.floor(arr.length/3)); //to get 4 nested arrays
console.log(chunked);
and another case:
var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17],
chunked = chunk(arr, 0, 3); // to get 6 nested arrays each containing maximum of 3 items
console.log(chunked);
Upvotes: 1
Reputation: 82913
For Underscore based solution try this:
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
var n = 3;
var lists = _.groupBy(data, function(element, index){
return Math.floor(index/n);
});
lists = _.toArray(lists); //Added this to convert the returned object to an array.
console.log(lists);
Using the chain wrapper method you can combine the two statements as below:
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
var n = 3;
var lists = _.chain(data).groupBy(function(element, index){
return Math.floor(index/n);
}).toArray()
.value();
Upvotes: 91