Reputation: 5223
Lets say I have this:
if(bool1 && bool2 && bool3) {
...
}
Now. Is Java smart enough to skip checking bool2 and bool3 if bool1 was evaluated to false? Does java even check them from left to right? I'm asking this because i was "sorting" the conditions inside my if statements by the time it takes to do them (starting with the cheapest ones on the left). Now I'm not sure if this gives me any performance benefits because i don't know how Java handles this.
Upvotes: 20
Views: 180463
Reputation: 340883
Yes, Java (similar to other mainstream languages) uses lazy evaluation short-circuiting which means it evaluates as little as possible.
This means that the following code is completely safe:
if(p != null && p.getAge() > 10)
Also, a || b
never evaluates b
if a
evaluates to true
.
Upvotes: 45
Reputation: 17444
Please look up the difference between &
and &&
in Java (the same applies to |
and ||
).
&
and |
are just logical operators, while &&
and ||
are conditional logical operators, which in your example means that
if(bool1 && bool2 && bool3) {
will skip bool2
and bool3
if bool1
is false, and
if(bool1 & bool2 & bool3) {
will evaluate all conditions regardless of their values.
For example, given:
boolean foo() {
System.out.println("foo");
return true;
}
if(foo() | foo())
will print foo
twice, and if(foo() || foo())
- just once.
Upvotes: 12
Reputation: 533670
Is Java smart enough to skip checking bool2 and bool2 if bool1 was evaluated to false?
Its not a matter of being smart, its a requirement specified in the language. Otherwise you couldn't write expressions like.
if(s != null && s.length() > 0)
or
if(s == null || s.length() == 0)
BTW if you use &
and |
it will always evaluate both sides of the expression.
Upvotes: 17
Reputation: 11155
Yes,that is called short-circuiting.
Please take a look at this wikipedia page on short-circuiting
Upvotes: 6