CODEWITHSUNDEEP
javastringtokenizer
user1109548
user1109548

Reputation: 1

String Tokenizing in java

I need to tokenize a string using a delimiter.

StringTokenizer is capable of tokenizing the string with given delimiter. But, when there are two consecutive delimiters in the string, then it is not considering it as a token.

Thanks in advance for you help

Regards,

Upvotes: 0

Views: 1289

Answers (3)

Mithun Sasidharan
Mithun Sasidharan

Reputation: 20920

The second parameter to the constructor of StringTokenizer object is just a string containing all delimiters that you require.

StringTokenizer st = new StringTokenizer(str, "@!");

In this case, there are two delimiters both @ and !

Consider this example :

String s = "Hello, i am using Stack Overflow;";
System.out.println("s = " + s);
String delims = " ,;";
StringTokenizer tokens = new StringTokenizer(s, delims);
while(tokens.hasMoreTokens())
  System.out.println(tokens.nextToken());

Here you would get an output similar to this with 3 delimiters :

Hello
,

i

am

using

Stack

Overflow

;

Upvotes: 3

mcfinnigan
mcfinnigan

Reputation: 11638

Use the split() method of java.lang.String and pass it a regular expression which matches your one or more delimiter condition.

for e.g. "a||b|||c||||d" could be tokenised with split("\\|{2,}"); with the resulting array [a,b,c,d]

Upvotes: 2

Francois
Francois

Reputation: 330

Look into String.split()

This should do what you are looking for.

http://docs.oracle.com/javase/6/docs/api/java/lang/String.html

Upvotes: 2

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