CODEWITHSUNDEEP
javaloggingslf4jsystem.out
Anton K.
Anton K.

Reputation: 963

How to make a Logger for System.out

I am wondering how to get org.slf4j.Logger for System.out. I know this is not good, but I need it for testing purposes.

Thank you so much.

Upvotes: 20

Views: 26433

Answers (4)

Sam
Sam

Reputation: 354

Put simplelogger.properties in your classpath and put this line in it:

org.slf4j.simpleLogger.logFile=System.out

This will cause SLF4J Simple Logger to log to Standard Output instead of Standard Error.

Upvotes: 16

aditsu quit because SE is EVIL
aditsu quit because SE is EVIL

Reputation: 4089

It is possible to use slf4j-simple and make it write to the standard output by setting a system property when the program starts:

System.setProperty("org.slf4j.simpleLogger.logFile", "System.out");

More information at http://www.slf4j.org/api/org/slf4j/impl/SimpleLogger.html

Upvotes: 21

Jean-Philippe Briend
Jean-Philippe Briend

Reputation: 3515

SLF4J is a logging facade. You need a logging implementation.

Nowadays, Logback is the recommanded logging framework.

To log to System.out, you have to use the ConsoleAppender in Logback configuration file.

Example :

<appender name="stdout" class="ch.qos.logback.core.ConsoleAppender">
  <target>System.out</target>
  <encoder>
    <pattern>%-40.40c [%5.5thread] %-5p %X - %m%n</pattern>
  </encoder>
</appender>

Upvotes: 6

Alex K.
Alex K.

Reputation: 3304

This might help: sysout-over-slf4j

Upvotes: 0

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