CODEWITHSUNDEEP
c#c#-3.0expression-trees
Spooles
Spooles

Reputation: 785

Binding parameter in Expression trees

I would like to know how to bind parameters to values within an expression tree

Something like

Expression<Func<String, String, bool>> e1 = (x,y) => x == y;

Then I would like to bind y, while preserving it as a single expression. A obvious attempt would be something like

Expresion<Func<String, bool>> e2 = x => e1(x, "Fixed Value Here");

But that would turn my expression into an Invoke node. Is there a way to simply bind a parameter within my first expression while getting the signature of the second expression?

Upvotes: 10

Views: 2471

Answers (1)

Marc Gravell
Marc Gravell

Reputation: 1062650

Expression<Func<String, String, bool>> e1 = (x,y) => x == y;

var swap = new ExpressionSubstitute(e1.Parameters[1],
    Expression.Constant("Fixed Value Here"));
var lambda = Expression.Lambda<Func<string, bool>>(
    swap.Visit(e1.Body), e1.Parameters[0]);

with

class ExpressionSubstitute : ExpressionVisitor
{
    public readonly Expression from, to;
    public ExpressionSubstitute(Expression from, Expression to)
    {
        this.from = from;
        this.to = to;
    }
    public override Expression Visit(Expression node)
    {
        if (node == from) return to;
        return base.Visit(node);
    }
}

this uses ExpressionVisitor to rebuild the expression, substituting y with the constant.

Another approach is to use Expression.Invoke, but this doesn't work in all cases.

Upvotes: 18

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