CODEWITHSUNDEEP
pythonsyntax
Billy Bach
Billy Bach

Reputation: 9

Syntax error in simple Python 3.2.2 program

This code is example code from a book on python. It is a simple program to enter integers and display the sum, total count, and average of the integers. However, when I try to run the code, I receive a syntax error at line 18, the colon. This code looks perfectly fine to me. Any ideas?

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: "
    if line:
        try:
            number = int(line)
        except ValueError as err:
            print(err)
            continue
    total += number
    count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

When i try and run this, I get an error:

  File "./intproj.py", line 18
    else:
       ^
SyntaxError: invalid syntax

I am using IDLE as an IDE with python 3.2.2 on Ubuntu 11.10

updated code:

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: ")
    if line:
        try:
            number = int(line)
        except ValueError as err:
                print(err)
                continue
    total += number
    count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

and now get the error:

  File "./intproj.py", line 18
    else:
       ^
SyntaxError: invalid syntax

Fixed code:

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: ")
    if line:
        try:
            number = int(line)
        except ValueError as err:
                print(err)
                continue
        total += number
        count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

Thanks!

Upvotes: 0

Views: 4132

Answers (5)

Fredrik Pihl
Fredrik Pihl

Reputation: 45662

line 9 seems to missing a )

change:

line = input("integer: "

into

line = input("integer: ")

The except line need to be indented to match the try

and the lines:

total += number
count += 1

needs to be indented as well otherwise, the if and the else statements don't line up. I.e. code should be something like this:

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: ")
    if line:
        try:
            number = int(line)
        except ValueError as err:
            print(err)
            continue
        total += number
        count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

Upvotes: 6

Philipp
Philipp

Reputation: 49812

The lines starting with total += and count += need to start with eight spaces instead of four.

Upvotes: 0

ianweller
ianweller

Reputation: 73

In addition to the closing parenthesis issue, your line that says except ValueError as err: is not indented enough (its indentation level should match that of the try statement). That should fix the line 18 else error you mentioned above.

Upvotes: 0

user334856
user334856

Reputation:

You need a closing bracket:

line = input("integer: ")

Upvotes: 1

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798676

You forgot to close your input() call on the previous line.

Upvotes: 1

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