CODEWITHSUNDEEP
c++arguments
Lorenzo Pistone
Lorenzo Pistone

Reputation: 5188

argument defaults to a precedent argument's value

I vaguely remember that it was possible to write something like:

void f(int a, int b=0, bool c=!val);

if some extra stuff was written at the beginning of the arguments list. The example in GCC gives error of val non declared in scope. Unfortunately, I cannot find any reference on the Internet, so I ask here.

Upvotes: 0

Views: 63

Answers (1)

Inbae Jeong
Inbae Jeong

Reputation: 4103

How about overloading f()? It won't be a problem whether val is const or not.

void f(int a, int b, bool c);

void f(int a, int b=0) {
   f(a,b,!val);
}

Upvotes: 1

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