CODEWITHSUNDEEP
phpfacebookfacebook-graph-apiparameter-passing
Anurag
Anurag

Reputation: 141

$uid not picking up the value

I am trying to download Facebook profile picture for Facebook application. For this, I'm getting the value of Facebook username/id in $uid. echo $uid is showing the correct result but it's not picking up the value when I use it in the following code:

echo $uid;
$imgDestinationPath = 'pic.jpg';
$link = 'http://graph.facebook.com/$uid/picture?type=large';
$content = file_get_contents($link);
file_put_contents($imgDestinationPath, $content);
error_reporting(E_ALL);

Moreover, when I put the Facebook username instead of $uid, it downloads the picture then. Please help. I'm new to PHP.

Upvotes: 0

Views: 185

Answers (2)

Mark
Mark

Reputation: 2704

$uid does not get evaluated, try this instead:

$link = 'http://graph.facebook.com/'.$uid.'/picture?type=large';

or you can do it with a double quote:

$link = "http://graph.facebook.com/$uid/picture?type=large";

I would prefer the first solution. This makes the code more readable to me.

Upvotes: 1

maxjackie
maxjackie

Reputation: 23312

please use the " " in this statement 

$link = "http://graph.facebook.com/$uid/picture?type=large";

will solve the problem

Upvotes: 1

Related Questions