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Ronin
Ronin

Reputation: 2067

Remove leading and trailing brackets in a String

In Java, I want to get rid of the leading and trailing brackets in a String.
Given input:

"[ hello, char[]={a,b,c} ... bye ]"

How can I produce the output of

" hello, char[]={a,b,c} ... bye "

only the leading [ and trailing ] is removed... How can I do that in Java?

Upvotes: 3

Views: 23485

Answers (6)

Makoto
Makoto

Reputation: 106400

Take a look at the String.substring() method:

System.out.println(input.substring(1, input.length() - 1))

Upvotes: 2

hbo
hbo

Reputation: 639

String s = "[ hello, char[]={a,b,c} ... bye ]";
s = s.replaceAll("^\\[|\\]$", "");

in case of having leading and/or trailing whitespaces:

String s = "   [ hello, char[]={a,b,c} ... bye ] ";
s = s.trim().replaceAll("^\\[|\\]$", "");

Upvotes: 5

Rajesh Pantula
Rajesh Pantula

Reputation: 10241

Infact,

this overload of substring(startIndex, endIndex);

input.substring(input.indexOf("[")+1,input.lastIndexOf("]"));

also if you want to remove the beginning and trailing spaces, use trim();

Upvotes: 3

bragboy
bragboy

Reputation: 35542

public class Test{
   public static void main(String[] args){
       String test = "[ abc ]";
       System.out.println(test.substring(1,test.length()-1));
       // Outputs " abc "
   }
}

Upvotes: 7

James Raitsev
James Raitsev

Reputation: 96391

String i = "[ hello, char[]={a,b,c} ... bye ]";

int indexOfOpenBracket = i.indexOf("[");
int indexOfLastBracket = i.lastIndexOf("]");

System.out.println(i.substring(indexOfOpenBracket+1, indexOfLastBracket));

Prints:

 hello, char[]={a,b,c} ... bye

Upvotes: 17

Sterling Duchess
Sterling Duchess

Reputation: 2080

String a = "[ hello, char[]={a,b,c} ... bye ] ";
a.substring(1,23);
System.out.println(a);

There you go i miss read.

Upvotes: 0

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