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objective-ciosarraysxcode
Aldee
Aldee

Reputation: 4538

Objective C: Displaying Array Elements

As far as my study is concern for Objective C, I found this code for displaying the array elements: 

NSMutableArray *myArray = [NSMutableArray arrayWithObjects:@"a", @"b", @"c"];
int x = 0;

for(; x<[myArray count]; x++)
    NSLog(@"value at index %i is %@", x, [myArray objectAtIndex:x]);

I am just curious if this is possible below: using [myArray[x]] instead of [myArray objectAtIndex:x] instead

for(; x < [myArray count]; x++)
    NSLog(@"value at index %i is %@", x, [myArray[x]]);

Upvotes: 0

Views: 3513

Answers (2)

Tom van der Woerdt
Tom van der Woerdt

Reputation: 29985

You cannot, and the reason is fairly simple: Objective-C is based on C and retains backwards compatibility.

In C, using [i] on an object will call the [] operator of that object. However, on the local scope all Objective-C objects are simply pointers, which would make the call something similar to int[3]. Does that look valid to you?

Implementing [] for NSArray would mean breaking backwards compatibility.

Upvotes: 1

matt
matt

Reputation: 536027

No, it isn't. An NSArray is not a C array; it's an object like any other object and you have to talk to it the way you'd talk to any other object, using full-fledged message syntax. (The only "shortcut" of the sort you're looking for is properties.) I'm sorry, but Objective-C is horribly verbose, and this is an excellent case in point. You'll become accustomed to using code completion as much as possible, to avoid typing all those letters...

Upvotes: 1

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