CODEWITHSUNDEEP
shellecho
dipt
dipt

Reputation: 1031

execute shell command with variable

To execute 'find' with some variables from txt file i made this but it doesn't work. is that wrong with execute statement?

#/bin/bash 
while read line; 
do 
   echo tmp_name: $line
   for ST in 'service.getFile("'$line;
           do
                   find ./compact/ -type f -exec grep -l $ST {} \;
           done
done < tmpNameList.txt

Upvotes: 1

Views: 359

Answers (2)

jfs
jfs

Reputation: 414207

grep can read multiple patterns from a file (-f option):

find ./compact/ -type f -exec grep -f patterns.txt {} +

where patterns.txt (prepend 'service.getFile(' to each line) is:

sed 's/^/service.getFile(/' tmpNameList.txt >patterns.txt

Upvotes: 0

fge
fge

Reputation: 121710

Try and quote $ST in your find command.

What's more:

  • since you operate from the current directory, ./ is not necessary;

  • you don't seem to have any special regex character (the ( needs to be quoted in grep's classical regex mode, and I assume you did mean a literal dot), so use fgrep instead (or grep -F). Ie:

               find compact/ -type f -exec fgrep -l "$ST" {} \;

Upvotes: 1

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