CODEWITHSUNDEEP
javascript
Kanishka Panamaldeniya
Kanishka Panamaldeniya

Reputation: 17586

How to set default values for parameters of a JavaScript function and call it with less parameters?

I have a function 

function test(name)
{

}

I call it with test("kanishka");

In one case, I want to pass two parameters (name and age) to this function: 

test("kanishka",27);

In PHP, I can do this by setting a default value to age :

test(name , age = NULL)

Is there any way in JavaScript to do this?

I tried 

test(name , age = NULL)

but it gives errors.

I can declare 2 functions

test(name) and  test(name , age = NULL)

but it duplicates the code.

Or I can change my previous function call which took one parameter to two parameters, giving a default value for age: 

test("kanishka" , 0)

but in this case I have to find all function call and change them.

Upvotes: 2

Views: 6618

Answers (6)

Gabriele Petrioli
Gabriele Petrioli

Reputation: 196217

Just changing the definition of the function will work

function test(name, age)
{

}

All existing uses of the function will assign to age an undefined value..

Whenever you use a second parameter it will be assigned to the age parameter.

If you want a default value change the function to

function test(name, age)
{
    age = (age === undefined) ? 0 : age; // change 0 to the default value you want..
}

Update

There is now support for default parameters

function test(name, age = 0)
{
  // age will be 0 if no second parameter is provided or it is undefined
}

Upvotes: 8

Billy Moon
Billy Moon

Reputation: 58611

You can use the arguments object which holds all arguments passed to a function - regardless of if they are defined or not...

test(name){
    var age = arguments[1] == undefined ? 0 : arguments[1]
    // do stuff here
}

Upvotes: 1

Paul Turner
Paul Turner

Reputation: 39675

The "standard" way to provide default values for methods is to check whether the arguments have been supplied at the start of the method body:

function test(name, age)
{
  age = typeof(age) != 'undefined' ? age : NULL;
  ...
}

Upvotes: 0

James Allardice
James Allardice

Reputation: 166031

You can either declare the function with the 2 arguments:

function test(name, age) {
   //...
}
test("James"); //age will be undefined
test("James", 22); //age will be 22

Or you could forget about the parameters altogether and use the arguments object:

function test() {
    console.log(arguments[0]);
}

This way you can pass in as many arguments as you like, and access them through the arguments object.

Upvotes: 1

Yazan Malkawi
Yazan Malkawi

Reputation: 501

basically you will do something like this

function foo(a, b)
 {
   a = typeof(a) != 'undefined' ? a : 42;
   b = typeof(b) != 'undefined' ? b : 'default_b';
   ...
 }

Upvotes: 4

Douglas
Douglas

Reputation: 37771

You can still call the method, even if you pass the wrong number of arguments. The "optional" argument will be set to undefined, which you can check for using an if statement.

Upvotes: 1

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