Reputation: 18973
I'd like to be able to do the following:
num_intervals = (cur_date - previous_date) / interval_length
or
print (datetime.now() - (datetime.now() - timedelta(days=5)))
/ timedelta(hours=12)
# won't run, would like it to print '10'
but the division operation is unsupported on timedeltas. Is there a way that I can implement divison for timedeltas?
Edit: Looks like this was added to Python 3.2 (thanks rincewind!): http://bugs.python.org/issue2706
Upvotes: 28
Views: 24687
Reputation: 131620
Sure, just convert to a number of seconds (minutes, milliseconds, hours, take your pick of units) and do the division.
EDIT (again): so you can't assign to timedelta.__div__
. Try this, then:
divtdi = datetime.timedelta.__div__
def divtd(td1, td2):
if isinstance(td2, (int, long)):
return divtdi(td1, td2)
us1 = td1.microseconds + 1000000 * (td1.seconds + 86400 * td1.days)
us2 = td2.microseconds + 1000000 * (td2.seconds + 86400 * td2.days)
return us1 / us2 # this does integer division, use float(us1) / us2 for fp division
And to incorporate this into nadia's suggestion:
class MyTimeDelta:
__div__ = divtd
Example usage:
>>> divtd(datetime.timedelta(hours = 12), datetime.timedelta(hours = 2))
6
>>> divtd(datetime.timedelta(hours = 12), 2)
datetime.timedelta(0, 21600)
>>> MyTimeDelta(hours = 12) / MyTimeDelta(hours = 2)
6
etc. Of course you could even name (or alias) your custom class timedelta
so it gets used in place of the real timedelta
, at least in your code.
Upvotes: 13
Reputation: 229724
Division and multiplication by integers seems to work out of the box:
>>> from datetime import timedelta
>>> timedelta(hours=6)
datetime.timedelta(0, 21600)
>>> timedelta(hours=6) / 2
datetime.timedelta(0, 10800)
Upvotes: 18
Reputation: 114961
You can override the division operator like this:
class MyTimeDelta(timedelta):
def __div__(self, value):
# Dome something about the object
Upvotes: 4