CODEWITHSUNDEEP
.netwinformsuser-controlspropertygriddesign-view
TheVillageIdiot
TheVillageIdiot

Reputation: 40507

Disable Property in Design View Property Grid

I want to expose some properties in my custom control. I require to get input for three parameters that I expose as Browsable properties from the control. Based on input for one property the other two might not be required. How can I disable/hide the properties that are not required based on selection for first property?

Upvotes: 2

Views: 299

Answers (1)

LarsTech
LarsTech

Reputation: 81620

Yes, with a little reflection, you can achieve this:

public class TestControl : Control {
  private string _PropertyA = string.Empty;
  private string _PropertyB = string.Empty;

  [RefreshProperties(RefreshProperties.All)]
  public string PropertyA {
    get { return _PropertyA; }
    set {
      _PropertyA = value;

      PropertyDescriptor pd = TypeDescriptor.GetProperties(this.GetType())["PropertyB"];
      ReadOnlyAttribute ra = (ReadOnlyAttribute)pd.Attributes[typeof(ReadOnlyAttribute)];
      FieldInfo fi = ra.GetType().GetField("isReadOnly", BindingFlags.NonPublic | BindingFlags.Instance);
      fi.SetValue(ra, _PropertyA == string.Empty);
    }
  }

  [RefreshProperties(RefreshProperties.All)]
  [ReadOnly(true)]
  public string PropertyB {
    get { return _PropertyB; }
    set { _PropertyB = value; }
  }
}

This will disable PropertyB whenever PropertyA is an empty string.

Found this article at the Code Project that described this process.

Upvotes: 3

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