CODEWITHSUNDEEP
pythonloopsfor-loop
stackuser10210
stackuser10210

Reputation: 352

Python arguments, for in items

I'd like to pass a list of integers as an argument to a python script.

Example code:

items = sys.argv[1]
for item in items:
    print item

My command would be:

python myscript.py 101,102,103

The problem is that 'for in' is giving me each digit rather than each item as delimited by the commas.

I'm sure there's an easy answer. How do I loop through the delimted values rather than single digits?

Thanks very much!

Upvotes: 2

Views: 3827

Answers (4)

user559611
user559611

Reputation:

The command line argument is passed to your script as a single string so you need to split it using the ',' as a delimiter to return individual integers.

items = sys.argv[1]
for item in items.split(','):
    print item

Upvotes: 2

Mark Ransom
Mark Ransom

Reputation: 308266

Normally the command line arguments are separated by spaces. The comma separated numbers are coming in as a single string, and the for is splitting the string into characters. You need to split it by commas: items.split(','). Once you do that you'll find that you still have strings, so you need to convert each string to an integer.

items = argv[1]
for item in items.split(','):
    print int(item)

Upvotes: 6

Óscar López
Óscar López

Reputation: 236034

Split the input:

items = sys.argv[1].split(',')
for item in items:
    print item

Upvotes: 2

Cydonia7
Cydonia7

Reputation: 3826

I think you should use directly :

python myscrypt.py 101 102 103

and

items = sys.argv

Upvotes: 3

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