CODEWITHSUNDEEP
cwindows
swe
swe

Reputation: 149

The code shows no error on compilation,but it doesn't show any output

The program is very simple , it gives the greatest common divisor as the output.I have verified my algorithm.The compiler issues no error ,but still it wont produce any output. 

#include<conio.h>
#include <stdio.h>
int gcd(int ,int );
int main()
{
    int a,b,j;
    printf("enter two numbers");
    scanf("%d\n",&a);
    scanf("%d\n",&b);
    j=gcd(a,b);
    printf("gcd is %d",j);
    getch();
    return 0;
}
int gcd(int x, int y)
{
    int temp,c;
    if(x<y)
    {
           temp=x;
           x=y;
           y=temp;
           }
    if(y<=x&&(x%y==0))
    return y;
    else
    {   temp=x%y;
        c=gcd(y,temp);
        return c;

        }
}

Upvotes: 1

Views: 2650

Answers (4)

BLUEPIXY
BLUEPIXY

Reputation: 40155

scanf("%d\n",&a);
scanf("%d\n",&b);

to

scanf("%d%*c",&a);
scanf("%d%*c",&b);

Upvotes: 0

onemach
onemach

Reputation: 4325

The problem is 

scanf("%d\n",&a);
scanf("%d\n",&b);

Delete the \n, just

scanf("%d",&a);
scanf("%d",&b);

is OK

Upvotes: 1

Mysticial
Mysticial

Reputation: 471559

This could be due to buffering of the output. Add \n to your printfs and see if it fixes it:

printf("enter two numbers\n");
printf("gcd is %d\n",j);

Alternatively, you can add calls to fflush(stdout) to flush the output buffer:

printf("enter two numbers");
fflush(stdout);

printf("gcd is %d",j);
fflush(stdout);

Other than that, it (almost) works as intended on my setup:

enter two numbers
4783780
354340
1
gcd is 20

The only thing is that the \n forces it to read an extra character. (which I chose to be 1)

Upvotes: 2

Oliver Charlesworth
Oliver Charlesworth

Reputation: 272802

This line:

printf("enter two numbers");

doesn't print a newline character (\n), and so the output isn't flushed to the console.

Try adding this after the printf:

fflush(stdout);

Upvotes: 0

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