ronag
ronag

Reputation: 51273

get value_type of dereferencable types

I how would I achieve the following for any derefernable type?

I find my current solution lacking since I need to do a class template specialization for every type I want it to work with:

template<typename T>
struct get_value_type
{
    typedef typename T::value_type value_type;
};

template<typename E>
struct get_value_type<std::unique_ptr<E>>
{
    typedef typename E::value_type value_type;
};  

template<typename E>
struct get_value_type<std::shared_ptr<E>>
{
    typedef typename E::value_type value_type;
};  

template<typename E>
struct get_value_type<boost::optional<E>>
{
    typedef typename E::value_type value_type;
};

I've tried the something along the ways of, which doesn't work.

template<typename T, typename IsIndirect = false_type>
get_value_type
{
    typedef typename T::value_type value_type;     
}

template<typename T>
struct get_value_type<T, true_type>
{
     typedef decltype(*boost::declval<E>())::value_type value_type; 
};

typedef get_value_type<T, is_indirect<T>::type> value_type;

Upvotes: 4

Views: 3709

Answers (2)

Howard Hinnant
Howard Hinnant

Reputation: 219335

You're looking for std::pointer_traits<PointerType>::element_type which lives in <memory>.

#include <memory>
#include <boost/optional.hpp>

template <class Ptr>
struct MyPointer
{
};

template <class Ptr>
struct YourPointer
{
    typedef signed char element_type;
};

int main()
{
    static_assert
    (
        std::is_same
        <
            std::pointer_traits<std::unique_ptr<double>>::element_type,
            double
        >::value,
        ""
    );
    static_assert
    (
        std::is_same
        <
            std::pointer_traits<std::unique_ptr<short[]>>::element_type,
            short
        >::value,
        ""
    );
    static_assert
    (
        std::is_same
        <
            std::pointer_traits<std::shared_ptr<const char>>::element_type,
            const char
        >::value,
        ""
    );
    static_assert
    (
        std::is_same
        <
            std::pointer_traits<boost::optional<int*>>::element_type,
            int*
        >::value,
        ""
    );
    static_assert
    (
        std::is_same
        <
            std::pointer_traits<MyPointer<long long>>::element_type,
            long long
        >::value,
        ""
    );
    static_assert
    (
        std::is_same
        <
            std::pointer_traits<YourPointer<long long>>::element_type,
            signed char
        >::value,
        ""
    );
}

20.6.3.1 Pointer traits member types [pointer.traits.types]

typedef see below element_type;

Type: Ptr::element_type if such a type exists; otherwise, T if Ptr is a class template instantiation of the form SomePointer<T, Args>, where Args is zero or more type arguments; otherwise, the specialization is ill-formed.

Oh, and there's a specialization for pointer types as well:

template <class T>
struct pointer_traits<T*>
{
    typedef T*        pointer;
    typedef T         element_type;
    typedef ptrdiff_t difference_type;

    template <class U> using rebind = U*;

    static pointer pointer_to(see below r) noexcept;
};

Upvotes: 7

Kerrek SB
Kerrek SB

Reputation: 477444

One solution which may be overly broad is to use a template template argument:

template <template <typename> class C, typename T>
struct get_value_type<C<T>>
{
    typedef T value_type;
};

The more flexible solution would use variadics:

template <typename> struct get_first_param;

template <template <typename...> class C, typename T, typename ...Args>
struct get_first_param<C<T, Args...>>
{
    typedef T value_type;
};

Upvotes: 2

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