souser
souser

Reputation: 6124

Perl query about data structure

I currently use the following hash which works fine

%hash = ( 
    'env1' => 'server1:port1, server11:port11',
    'env2' => 'server2:port2, server22:port22'
) ;

However, what I really want to do is create the following data structure, which will make it easier for me to extract the information. The following obviously does not work.

(
  env1 => "server=server1, port=port1", "server=server11, port=port11",
  env2 => "server=server2, port=port2", "server=server22, port=port22"
) ;

Wondering if anyone has any suggestions on creating a data structure that would match my requirements.

Upvotes: 0

Views: 142

Answers (2)

Dan
Dan

Reputation: 10786

Write this:

%hash = (
  env1 => ["server=server1, port=port1", "server=server11, port=port11"],
  env2 => ["server=server2, port=port2", "server=server22, port=port22"]
) ;

And then access elements like this:

$hash{'env1'}->[0] == "server=server1, port=port1"
$hash{'env2'}->[1] == "server=server22, port=port22"

This is a hash where the values are references to anonymous arrays.

But when I look at you data I think maybe there is a better way to store it:

%hash = (
  env1 => [{'server' => 'server1', 'port' => 'port1'}, {'server' => 'server11', 'port' => 'port11'}],
  env2 => [{'server' => 'server2', 'port' => 'port2'}, {'server' => 'server22', 'port' => 'port22'}]
) ;

And then access elements like this:

$hash{'env1'}->[0]->{'server'} == "server1"
$hash{'env2'}->[1]->{'port'} == "port22"

Upvotes: 10

Matt Varblow
Matt Varblow

Reputation: 7901

Hard to tell exactly what you're looking for given the question. I suspect a hash of hashes will suffice. You'd set it up like this:

%hash = ( 'env1' => { 'server' => 'server1', 'port' => 'port1' }, 
          'env2' => { 'server' => 'server2', 'port' => 'port2' } );

To get the values, you'd do something like this:

print $hash{'env2'}->{'server'};

You can add additional values like this:

$hash{'env3'} = {'server' => 'server3', 'port' => 'port3'};

Upvotes: 0

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