Reputation: 95
I have this simple code:
<?
if (isset($_POST["phpinfo"])) phpinfo(); else echo "you haven't chosen what to do yet";
?>
<h1>Test page 1</h1>
<form method="post" action="">
<select>
<option>Choose what to do</option>
<option value='phpinfo'>phpinfo();</option></select></form>
The problem is that if I use JavaScript (onChange="this.form.submit()") to auto-submit the post data it doesn't submit but if I use a submit button it does submit to self.
<input type="submit" name='phpinfo' id="phpinfo">
My question is, what do I have to do so I can have an auto-submitting drop down list that submits POST data to self?
Thanks in advance!
Upvotes: 2
Views: 3143
Reputation: 166
<?php
if(isset($_POST['selctVal']) && $_POST['selctVal']!="" )
{
echo "Form Submited =><br/>";
echo "Form Submited =>".$_POST['selctVal'];
}
else
{
echo "you haven't chosen what to do yet";
}
?>
<form method="post" action="" name="anyformname">
<select name="selctVal" onchange="document.anyformname.submit();">
<option>Choose what to do</option>
<option value='<?php echo phpinfo();?>'>phpinfo();</option>
</select>
</form>
Upvotes: 0
Reputation: 1658
<?php
if($_POST['txtVal'] != "") {
echo "Form Submited";
}
?>
<form method="post" action="">
<select name="txtVal" onchange="this.form.submit();">
<option>Choose what to do</option>
<option value='phpinfo'>phpinfo();</option></select>
</form>
Hope it will works for you.
Upvotes: 1
Reputation: 31730
Your select needs to be named. The select name is what's returned to PHP, and its value will be the value of the option selected.
<select name="performaction">
<option value="phpinfo">phpinfo ()</option>
</select>
if ($_POST [performaction] == 'phpinfo')
{
phpinfo ();
}
Upvotes: 5
Reputation: 100175
Try:
//add a name to form
<form method="post" action="" name="some_name">
//then on your select's onchange function do:
document.forms['some_name'].submit();
Hope it helps
Upvotes: 0