CODEWITHSUNDEEP
javaxmlurlvariablessaxparser
chuck
chuck

Reputation: 1

Passing a http url into SAXParser XML

I'm having a problem passing an XML page into the SAXParser as a variable. My code below obtains a URL and tries to pass it into the SAXParser, but I get an error.

However, when I explicitly define the URL (rather than use the variable), if works fine. Does anyone no why this is failing.

Thanks to anyone who may be able to help. I've trimmed the code for viewing purposes.

public class Parser extends DefaultHandler
  private String link;

    public void parseDocument() {

        SAXParserFactory spf = SAXParserFactory.newInstance();
        try {

            SAXParser sp = spf.newSAXParser();

            link = coll.getGcollId(id);  // this successfully gets a string (url) to link to xml page over http string          
            //parse the file and also register this class for call backs
            sp.parse(link, this);  // when I run this code this line gets a "java.io.FileNotFoundException: http://foo.com/foo.xml"

Upvotes: 0

Views: 4287

Answers (1)

sverdianto
sverdianto

Reputation: 134

Use the following instead

SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
String link = coll.getGcollId(id);
URL linkURL = new URL(link);

sp.parse(new InputSource(url.openStream()));

Upvotes: 3

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