Reputation: 383
I'm trying to implement a map with a lambda function in C++11 as such
std::map<int, int, [](const int&a, const int& b) { return a < b; }> test;
but that fails with
error: type/value mismatch at argument 3 in template parameter list for
‘template<class _Key, class _Tp, class _Compare, class _Alloc> class std::map’
error: expected a type, got
‘{}’
error: invalid type in declaration before
‘;’
token
Any advice?
Upvotes: 30
Views: 26682
Reputation: 103693
You need to pass the type of the lambda as a template argument, not the lambda itself. What you want is this:
auto mycomp = [](const int&a, const int& b) { return a < b; };
std::map<int, int, decltype(mycomp)> test(mycomp);
Although in fact, since your lambda has no captures, it can actually be stored in a function pointer, so alternatively, you could do this:
std::map<int, int, bool(*)(const int&,const int&)>
test([](const int&a, const int& b) { return a < b; });
Though I find the first much more readable. Although using the function pointer type is more versatile. i.e. It can accept any function pointer or non-capturing lambda that matches that signature. But if you change your lambda to be capturing, it will not work. For a more versatile version, you could use std::function
, i.e:
std::map<int, int, std::function<bool(const int&, const int&)>>
That will work with any function, lambda(capturing or not) or function object, as long as the signature matches.
Upvotes: 43