CODEWITHSUNDEEP
pythonsyntaxoperators
wim
wim

Reputation: 362786

"x not in y" or "not x in y"

When testing for membership, we can use:

x not in y

Or alternatively:

not x in y

There can be many possible contexts for this expression depending on x and y. It could be for a substring check, list membership, dict key existence, for example.

Upvotes: 123

Views: 22337

Answers (6)

trincot
trincot

Reputation: 350300

They are identical in meaning, but the pycodestyle Python style guide checker (formerly called pep8) prefers the not in operator in rule E713:

E713: test for membership should be not in

See also "Python if x is not None or if not x is None?" for a very similar choice of style.

Upvotes: 12

Tomas Aschan
Tomas Aschan

Reputation: 60594

Others have already made it very clear that the two statements are, down to a quite low level, equivalent.

However, I don't think that anyone yet has stressed enough that since this leaves the choice up to you, you should

choose the form that makes your code as readable as possible.

And not necessarily as readable as possible to anyone, even if that's of course a nice thing to aim for. No, make sure the code is as readable as possible to you, since you are the one who is the most likely to come back to this code later and try to read it.

Upvotes: 2

Ben
Ben

Reputation: 71495

They always give the same result.

In fact, not 'ham' in 'spam and eggs' appears to be special cased to perform a single "not in" operation, rather than an "in" operation and then negating the result:

>>> import dis

>>> def notin():
    'ham' not in 'spam and eggs'
>>> dis.dis(notin)
  2           0 LOAD_CONST               1 ('ham')
              3 LOAD_CONST               2 ('spam and eggs')
              6 COMPARE_OP               7 (not in)
              9 POP_TOP             
             10 LOAD_CONST               0 (None)
             13 RETURN_VALUE    

>>> def not_in():
    not 'ham' in 'spam and eggs'
>>> dis.dis(not_in)
  2           0 LOAD_CONST               1 ('ham')
              3 LOAD_CONST               2 ('spam and eggs')
              6 COMPARE_OP               7 (not in)
              9 POP_TOP             
             10 LOAD_CONST               0 (None)
             13 RETURN_VALUE    

>>> def not__in():
    not ('ham' in 'spam and eggs')
>>> dis.dis(not__in)
  2           0 LOAD_CONST               1 ('ham')
              3 LOAD_CONST               2 ('spam and eggs')
              6 COMPARE_OP               7 (not in)
              9 POP_TOP             
             10 LOAD_CONST               0 (None)
             13 RETURN_VALUE        

>>> def noteq():
    not 'ham' == 'spam and eggs'
>>> dis.dis(noteq)
  2           0 LOAD_CONST               1 ('ham')
              3 LOAD_CONST               2 ('spam and eggs')
              6 COMPARE_OP               2 (==)
              9 UNARY_NOT           
             10 POP_TOP             
             11 LOAD_CONST               0 (None)
             14 RETURN_VALUE

I had thought at first that they always gave the same result, but that not on its own was simply a low precedence logical negation operator, which could be applied to a in b just as easily as any other boolean expression, whereas not in was a separate operator for convenience and clarity.

The disassembly above was revealing! It seems that while not obviously is a logical negation operator, the form not a in b is special cased so that it's not actually using the general operator. This makes not a in b literally the same expression as a not in b, rather than merely an expression that results in the same value.

Upvotes: 131

Makoto
Makoto

Reputation: 106440

Syntactically they're the same statement. I would be quick to state that 'ham' not in 'spam and eggs' conveys clearer intent, but I've seen code and scenarios in which not 'ham' in 'spam and eggs' conveys a clearer meaning than the other.

Upvotes: 0

icktoofay
icktoofay

Reputation: 129001

  1. No, there is no difference.

    The operator not in is defined to have the inverse true value of in.

    —Python documentation

  2. I would assume not in is preferred because it is more obvious and they added a special case for it.

Upvotes: 25

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798706

In Python, there is no difference. And there is no preference.

Upvotes: 1

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