Reputation: 19443
I had the code:
std::string st = "SomeText";
...
std::cout << st;
and that worked fine. But now my team wants to move to wstring
.
So I tried:
std::wstring st = "SomeText";
...
std::cout << st;
but this gave me a compilation error:
Error 1 error C2664: 'std::basic_string<_Elem,_Traits,_Ax>::basic_string(const std::basic_string<_Elem,_Traits,_Ax> &)' : cannot convert parameter 1 from 'const char [8]' to 'const std::basic_string<_Elem,_Traits,_Ax> &' D:...\TestModule1.cpp 28 1 TestModule1
After searching the web I read that I should define it as:
std::wstring st = L"SomeText"; // Notice the "L"
...
std::cout << st;
this compiled but prints "0000000000012342"
instead of "SomeText"
.
What am I doing wrong ?
Upvotes: 87
Views: 128477
Reputation: 759
Another way to print wide string:
std::wstring str1 = L"SomeText";
std::wstring strr2(L"OtherText!");
printf("Wide String1- %ls \n", str1.c_str());
wprintf(L"Wide String2- %s \n", str2.c_str());
Upvotes: 4
Reputation: 22797
This answer apply to "C++/CLI" tag, and related Windows C++ console.
If you got multi-bytes characters in std::wstring, two more things need to be done to make it work:
#include <io.h>
#include <fcntl.h>
_setmode(_fileno(stdout), _O_U16TEXT)
Upvotes: 15
Reputation: 30648
try to use use std::wcout<<st
it will fix your problem.
std::wstring st = "SomeText";
...
std::wcout << st;
Upvotes: 8
Reputation: 92291
To display a wstring you also need a wide version of cout - wcout.
std::wstring st = L"SomeText";
...
std::wcout << st;
Upvotes: 154