Reputation: 7472
I have the following function:
$(document).ready(function() {
$("#dSuggest").keypress(function() {
var dInput = $('input:text[name=dSuggest]').val();
console.log(dInput);
$(".dDimension:contains('" + dInput + "')").css("display","block");
});
});
For some reason, for the first keypress, I'm getting an empty string to the console log.
Upvotes: 156
Views: 348312
Reputation: 1
$(document).on('keypress',((e)=>{
console.log(e.which)
}))
I read the JQuery Documentation (7th June 2023) and it used (e.which) and it returned the ASCII value of the key pressed. Hope it helps.
Upvotes: 0
Reputation: 1349
please use this code for input text
$('#search').on("input",function (e) {});
if you use .on("change",function (e) {});
then you need to blur input
if you use .on("keyup",function (e) {});
then you get value before the last character you typed
Upvotes: 0
Reputation: 21
Just use a timeout to make your call; the timeout will be called when the event stack is finished (i.e. after the default event is called)
$("body").on('keydown', 'input[type=tel]', function (e) {
setTimeout(() => {
formatPhone(e)
}, 0)
});
Upvotes: 1
Reputation: 304
I think what you need is the below prototype
$(element).on('input',function(){code})
Upvotes: 1
Reputation: 3083
I was looking for a ES6 example (so it could pass my linter) So for other people who are looking for the same:
$('#dSuggest').keyup((e) => {
console.log(e.currentTarget.value);
});
I would also use keyup because you get the current value that is filled in.
Upvotes: 7
Reputation: 6292
This is because Keypress
event is fired before the new character is added. Use 'keyup' event instead,which will work perfectly in your situation.
$(document).ready(function() {
$("#dSuggest").keyup(function() {
var dInput = $('input:text[name=dSuggest]').val();
console.log(dInput);
$(".dDimension:contains('" + dInput + "')").css("display","block");
});
});
I want to add to this, if you have many textboxes and you have to do the same thing on their keyup event you can simply give them a common css class(eg commoncss) and apply keyup event like this.
$(document).ready(function() {
$(".commoncss").keyup(function() {
//your code
});
});
this will greatly reduce you code as you don't have to apply keyup event by id for each textboxes.
Upvotes: 4
Reputation: 2947
Realizing that this is a rather old post, I'll provide an answer anyway as I was struggling with the same problem.
You should use the "input"
event instead, and register with the .on
method. This is fast - without the lag of keyup
and solves the missing latest keypress problem you describe.
$('#dSuggest').on("input", function() {
var dInput = this.value;
console.log(dInput);
$(".dDimension:contains('" + dInput + "')").css("display","block");
});
Upvotes: 231
Reputation: 22914
You have to interrupt the execution thread to allow the input to update.
$(document).ready(function(event) {
$("#dSuggest").keypress(function() {
//Interrupt the execution thread to allow input to update
setTimeout(function() {
var dInput = $('input:text[name=dSuggest]').val();
console.log(dInput);
$(".dDimension:contains('" + dInput + "')").css("display","block");
}, 0);
});
});
Upvotes: 5
Reputation: 79830
Use .keyup
instead of keypress.
Also use $(this).val()
or just this.value
to access the current input value.
DEMO here
Info about .keypress
from jQuery docs,
The keypress event is sent to an element when the browser registers keyboard input. This is similar to the keydown event, except in the case of key repeats. If the user presses and holds a key, a keydown event is triggered once, but separate keypress events are triggered for each inserted character. In addition, modifier keys (such as Shift) trigger keydown events but not keypress events.
Upvotes: 37
Reputation: 237845
This is because keypress
events are fired before the new character is added to the value
of the element (so the first keypress
event is fired before the first character is added, while the value
is still empty). You should use keyup
instead, which is fired after the character has been added.
Note that, if your element #dSuggest
is the same as input:text[name=dSuggest]
you can simplify this code considerably (and if it isn't, having an element with a name that is the same as the id
of another element is not a good idea).
$('#dSuggest').keypress(function() {
var dInput = this.value;
console.log(dInput);
$(".dDimension:contains('" + dInput + "')").css("display","block");
});
Upvotes: 178