CODEWITHSUNDEEP
javascriptprototype
LB.
LB.

Reputation: 14112

Javascript Prototype Programming

I'm trying to include some namespace into my Javascript API.

Here's what I have so far:

if (!Sample || Sample == "undefined")
    var Sample = {};

Sample.SomeApi = {};

Sample.SomeApi.prototype = {
    SomeMethod: function() {
        alert('some api');
    }
};

What's going on here?

When I'm calling Sample.SomeApi.SomeMethod(); // it won't work as it will complain:

Uncaught TypeError: Object #<Object> has no method 'SomeMethod'
(anonymous function)Course:43
onclick

Upvotes: -1

Views: 204

Answers (3)

AmGates
AmGates

Reputation: 2123

Try this

if(typeof Sample == 'undefined')
        var Sample ={}
    Sample.SomeApi = function(a)
    {
        this.a =a;
    }

Sample.SomeApi.prototype.SomeMethod = function() {
        alert('some api');
    }
    var d = new Sample.SomeApi(1);
    d.SomeMethod();

Hope this helps you

Go through this link here

Upvotes: 0

Luis Perez
Luis Perez

Reputation: 28120

I think you meant __proto__ not prototype, like so:

if (!Sample || Sample == "undefined")
    var Sample = {};

Sample.SomeApi = {};

Sample.SomeApi.__proto__ = {
    SomeMethod: function() {
        alert('some api');
    }
};

Sample.SomeApi.SomeMethod();

You can test it out in this jsFiddle: http://jsfiddle.net/luisperezphd/xtyyf/

But why not just this:

if (!Sample || Sample == "undefined")
    var Sample = {};

Sample.SomeApi = {
    SomeMethod: function() {
        alert('some api');
    }
};

Sample.SomeApi.SomeMethod();

It's much cleaner.

And there is the jsFiddle for that: http://jsfiddle.net/luisperezphd/HUuMQ/

Upvotes: 2

Daff
Daff

Reputation: 44205

You have to create a constructor for Sample.SomeApi not assign an empty object:

if(typeof Sample == 'undefined')
    Sample = {};

Sample.SomeApi = function() {
};

Sample.SomeApi.prototype = {
    someMethod : function() {
            alert('some api');
    }
}

new Sample.SomeApi().someMethod();

Upvotes: 1

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