Reputation: 25265
I'm working with some very unintuitive xml (all the tags are things like "TX", "H", "VC").
I'd like to make a copy of this data, but with all of the tags renamed to what they actually mean. Can I create a new, empty document to put my new, nicely named tags in to?
I've tried this:
doc = (new DOMParser()).parseFromString("", 'text/xml');
but when I do so, I wind up with a document that has a child node, rather than being empty. Furthermore, that child's tagname is "parsererror"
So, any ideas how I can create an empty document?
Upvotes: 6
Views: 12110
Reputation: 9150
The WHATWG's specification of the createDocument
method allows one to provide null
for each of the 3 arguments to createDocument
, to have an "empty" XML document created and returned -- one without any root node and with the application/xml
as its content type.
When the document
object is available (a compliant Web user agent), the implementation with the createDocument
method can be referred to with document.implementation
:
document.implementation.createDocument(null, null, null);
You may then trivially attach a root node of your choosing to it by simply appending it as you otherwise would, as follows (empty_doc
would refer to the document created and returned by the call above):
empty_doc.appendChild(empty_doc.createElement("foobar"));
Upvotes: 2
Reputation: 594
var xmldom = require('xmldom');
var tree = (new xmldom.DOMImplementation()).createDocument();
Upvotes: 1
Reputation: 3282
You can create an empty document in a W3C DOM compliant browser (IE9+ and the rest) with the following code.
var doc = (new DOMParser()).parseFromString('<dummy/>', 'text/xml');
doc.removeChild(doc.documentElement);
Upvotes: 3
Reputation: 61
I hade the same issue and I solved it like below:
xmlDoc = document.implementation.createDocument("", "", null);
root = xmlDoc.createElement("description");
xmlDoc.appendChild(root);
alert((new XMLSerializer()).serializeToString(xmlDoc));
Upvotes: 6
Reputation: 200846
I don't think you can create a document without the root node. You could create a fake node:
doc = (new DOMParser()).parseFromString("<dummy/>", 'text/xml');
However, a better solution might be to create constants for the node names:
// Use different variable names, like RealTxName, if desired
var REAL_TX_NAME = "TX";
var REAL_H_NAME = "H";
...
doc.find (REAL_TX_NAME);
...
Upvotes: 1