Reputation: 6156
I have a list of standard names
standard = ["Richard","Robert","Nicolas"]
and a dictionary of aliases (in this case nicknames)
aliases = {standard[0]:["Richard","Rick","Dick","Rich"],
standard[1]:["Robert","Roberto","Bob"],
standard[2]:["Nicolas","Nick","Nic"]}
I want to make a new dictionary that I can put any of the alias names in as a key and it will return the standard name AKA swap the key and value
My only guess so far was this
t = {}
aliases = [t.update(zip(v,[k]*len(v))) for k,v in aliases.items()]
aliases = t
is there a neater or more readable way to do this (id prefer not having the temporary dictionary t).
Upvotes: 4
Views: 257
Reputation: 67083
A fun way to abuse itertools:
>>> from itertools import izip, repeat, chain
>>> dict(chain.from_iterable(
izip(iter(b), repeat(a, len(b)))
for a, b in aliases.iteritems()))
{'Nicolas': 'Nicolas',
'Richard': 'Richard',
'Nic': 'Nicolas',
'Robert': 'Robert',
'Dick': 'Richard',
'Roberto': 'Robert',
'Nick': 'Nicolas',
'Rick': 'Richard',
'Rich': 'Richard',
'Bob': 'Robert'}
Upvotes: 0
Reputation: 28703
dict((nick, name) for name, nicks in aliases.iteritems() for nick in nicks)
Upvotes: 1
Reputation: 4673
>>> standard = ["Richard","Robert","Nicolas"]
>>> aliases = {standard[0]:["Richard","Rick","Dick","Rich"],
standard[1]:["Robert","Roberto","Bob"] ,
standard[2]:["Nicolas","Nick","Nic"] }
>>> def name(nickname):
return [n for n in aliases if nickname in aliases[n]]
>>> name('Bob')
['Robert']
>>>
List comprehensions are awesome.
Upvotes: 1
Reputation: 602105
I think this would be more readable:
rev_aliases = {}
for name, nick_list in aliases.iteritems():
for nick in nick_list:
rev_aliases[nick] = name
If you prefer some form of generator expression you can use these:
Python >= 2.7:
rev_aliases = {nick: name
for name, nick_list in aliases.viewitems()
for nick in nick_list}
Python < 2.7:
rev_aliases = dict((nick, name)
for name, nick_list in aliases.iteritems()
for nick in nick_list)
Upvotes: 6