CODEWITHSUNDEEP
perlbash
CodeBlocks
CodeBlocks

Reputation: 79

run multiple scripts

I have a number of bash scripts. for example

script1_1.sh
script1_2.sh
script1_3.sh

etc....

I was wondering, is there a way for me to run these all in another script. where by I don't have to manually add each. So through the use of a for loop? where it increments a number like

for (i=0; i < 40; i++)
   ./script1_[i].sh

I would also like to check each script worked, so if not, it would exit the for loop.

if ./script[i] (command unsuccessful)
then break?

Can anyone help me write this code? i'm very new to scripting languages.

Upvotes: 0

Views: 122

Answers (2)

jordanm
jordanm

Reputation: 34914

You are really close to answering your own question. The C-style for loop will work fine for your scenario, but if your scripts are randomly named, you can use an array. You can use ||, which will execute the right side if a non-zero exit status is returned. You could also use an if statement like you have proved in your question, with a "!" between if in the command (if not).

scripts=( script1_1.sh script1_2.sh script1_3.sh )

for script in "${scripts[@]}"; do
   ./"$script" || { echo "$script failed"; break; }
done

Using the for loop like in your questions:

for ((i=1;i<4;i++)); do
   ./script1_${i}.sh || { echo "$script failed"; break; }
done

Upvotes: 3

user554546
user554546

Reputation:

Since you have this question tagged with perl, you can also do this in a Perl one-liner:

perl -e 'foreach(1..40){system("sh script_" . $_ . ".sh")==0 or die $!;print "script_" . $_ . ".sh done\n";}'

Upvotes: 0

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