CODEWITHSUNDEEP
python
Bruno 'Shady'
Bruno 'Shady'

Reputation: 4516

How check a string value inside a list on a if statement?

I have the following code:

s = ['01','06','11','16','21','26','31','36','41','46','51','56']

while True:
    for a in s:
        if time.strftime('%S') == a:             
            print 'YES'
        else:
            print time.strftime('%S')
            time.sleep(1)
            print a

And it doesn't work.

Any ideas how to make it work?
In case, everytime the %S gets some of the value in s, it prints the 'YES'.

Upvotes: 0

Views: 101

Answers (1)

ekhumoro
ekhumoro

Reputation: 120608

You need to call sleep on every loop and look for the current seconds in your list of matches:

>>> import time
>>>
>>> matches = ['01','06','11','16','21','26','31','36','41','46','51','56']
>>>
>>> while True:
...     seconds = time.strftime('%S')
...     if seconds in matches:
...         print('YES')
...     else:
...         print(seconds)
...     time.sleep(1)
...
07
08
09
10
YES
12
13
14
15
YES
17
18
19

Upvotes: 2

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