kirby
kirby

Reputation: 4041

Is it possible to use a div as content for Twitter's Popover

I am using twitter's bootstrap's popover here. Right now, when i scroll over the popover text a popover appears with just text from the <a>'s data-content attribute. I was wondering if there was anyway to put a <div> inside the popover. Potentially, I would like to use php and mysql in there, but if i could get a div to work i think i can figure out the rest. I tried setting data-content to a div ID, but it didnt work.

HTML:

<a class='danger' 
   data-placement='above' 
   rel='popover' 
   data-content='#PopupDiv' 
   href='#'>Click</a>

Upvotes: 152

Views: 141633

Answers (8)

j&#228;vi
j&#228;vi

Reputation: 4565

First of all, if you want to use HTML inside the content you need to set the HTML option to true:

$('.danger').popover({ html : true});

Then you have two options to set the content for a Popover

  • Use the data-content attribute. This is the default option.
  • Use a custom JS function which returns the HTML content.

Using data-content: You need to escape the HTML content, something like this:

<a class='danger' data-placement='above' 
   data-content="&lt;div&gt;This is your div content&lt;/div&gt;" 
   title="Title" href='#'>Click</a>

You can either escape the HTML manually or use a function. I don't know about PHP but in Rails we use html_safe.

Using a JS function: If you do this, you have several options. The easiest I think is to put your div content hidden wherever you want and then write a function to pass its content to popover. Something like this:

$(document).ready(function(){
  $('.danger').popover({ 
    html : true,
    content: function() {
      return $('#popover_content_wrapper').html();
    }
  });
});

And then your HTML looks like this:

<a class='danger' data-placement='above' title="Popover Title" href='#'>Click</a>
<div id="popover_content_wrapper" style="display: none">
  <div>This is your div content</div>
</div>

PS: I've had some troubles when using popover and not setting the title attribute... so, remember to always set the title.

Upvotes: 308

shrewmouse
shrewmouse

Reputation: 6030

All of these answers miss a very important aspect!

By using .html or innerHtml or outerHtml you are not actually using the referenced element. You are using a copy of the element's html. This has some serious draw backs.

  1. You can't use any ids because the ids will be duplicated.
  2. If you load the contents every time that the popover is shown you will lose all of the user's input.

What you want to do is load the object itself into the popover.

https://jsfiddle.net/shrewmouse/ex6tuzm2/4/

HTML:

<h1> Test </h1>

<div><button id="target">click me</button></div>

<!-- This will be the contents of our popover -->
<div class='_content' id='blah'>
<h1>Extra Stuff</h1>
<input type='number' placeholder='number'/>
</div>

JQuery:

$(document).ready(function() {

    // We don't want to see the popover contents until the user clicks the target.
    // If you don't hide 'blah' first it will be visible outside of the popover.
    //
    $('#blah').hide();

    // Initialize our popover
    //
    $('#target').popover({
        content: $('#blah'), // set the content to be the 'blah' div
        placement: 'bottom',
        html: true
    });
    // The popover contents will not be set until the popover is shown.  Since we don't 
    // want to see the popover when the page loads, we will show it then hide it.
    //
    $('#target').popover('show');
    $('#target').popover('hide');

    // Now that the popover's content is the 'blah' dive we can make it visisble again.
    //
    $('#blah').show();


});

Upvotes: 6

Sulung Nugroho
Sulung Nugroho

Reputation: 1683

Why so complicated? just put this :

data-html='true'

Upvotes: -2

Dinesh Sarak
Dinesh Sarak

Reputation: 17

here is an another example

<a   data-container = "body" data-toggle = "popover" data-placement = "left" 
    data-content = "&lt;img src='<?php echo baseImgUrl . $row1[2] ?>' width='250' height='100' &gt;&lt;div&gt;&lt;h3&gt; <?php echo $row1['1'] ?>&lt/h3&gt; &lt;p&gt; &lt;span&gt;<?php echo $countsss ?>videos &lt;/span&gt;
&lt;span&gt;<?php echo $countsss1 ?> followers&lt;/span&gt;
&lt;/p&gt;&lt;/div&gt;
<?php echo $row1['4'] ?>   &lt;hr&gt;&lt;div&gt;
&lt;span&gt; &lt;button type='button' class='btn btn-default pull-left green'&gt;Follow  &lt;/button&gt;  &lt;/span&gt; &lt;span&gt; &lt;button type='button' class='btn btn-default pull-left green'&gt; Go to channel page&lt;/button&gt;   &lt;/span&gt;&lt;span&gt; &lt;button type='button' class='btn btn-default pull-left green'&gt;Close  &lt;/button&gt;  &lt;/span&gt;

 &lt;/div&gt;">

<?php echo $row1['1'] ?>
  </a>

Upvotes: -2

Birbone
Birbone

Reputation: 83

In addition to other replies. If you allow html in options you can pass jQuery object to content, and it will be appended to popover's content with all events and bindings. Here is the logic from source code:

  • if you pass a function it will be called to unwrap content data
  • if html is not allowed content data will be applied as text
  • if html allowed and content data is string it will be applied as html
  • otherwise content data will be appended to popover's content container
$("#popover-button").popover({
    content: $("#popover-content"),
    html: true,
    title: "Popover title"
});

Upvotes: 8

Roman K
Roman K

Reputation: 404

Late to the party. Building off the other solutions. I needed a way to pass the target DIV as a variable. Here is what I did.

HTML for Popover source (added a data attribute data-pop that will hold value for destination DIV id/or class):

<div data-html="true" data-toggle="popover" data-pop="popper-content" class="popper">

HTML for Popover content (I am using bootstrap hide class):

<div id="popper-content" class="hide">Content goes here</div>

Script:

$('.popper').popover({
placement: popover_placement,
container: 'div.page-content',
html: true,
trigger: 'hover',
content: function () {
    var pop_dest = $(this).attr("data-pop");
    //console.log(plant);
    return $("#"+pop_dest).html();
}});

Upvotes: 11

isherwood
isherwood

Reputation: 61083

Building on jävi's answer, this can be done without IDs or additional button attributes like this:

http://jsfiddle.net/isherwood/E5Ly5/

<button class="popper" data-toggle="popover">Pop me</button>
<div class="popper-content hide">My first popover content goes here.</div>

<button class="popper" data-toggle="popover">Pop me</button>
<div class="popper-content hide">My second popover content goes here.</div>

<button class="popper" data-toggle="popover">Pop me</button>
<div class="popper-content hide">My third popover content goes here.</div>

$('.popper').popover({
    container: 'body',
    html: true,
    content: function () {
        return $(this).next('.popper-content').html();
    }
});

Upvotes: 42

A Bright Worker
A Bright Worker

Reputation: 1318

Another alternate method if you wish to just have look and feel of pop over. Following is the method. Offcourse this is a manual thing, but nicely workable :)

HTML - button

<button class="btn btn-info btn-small" style="margin-right:5px;" id="bg" data-placement='bottom' rel="tooltip" title="Background Image"><i class="icon-picture icon-white"></i></button>

HTML - popover

<div class="bgform popover fade bottom in">
            <div class="arrow"></div>
             ..... your code here .......
</div>

JS

$("#bg").click(function(){
        $('.bgform').slideToggle();
});

Upvotes: 11

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