Reputation: 1841
I am trying to write a simple multithreaded program in C#. It has a button pressing which creates a new label on form, and then a for loop runs displaying loop value in label. So if you press button 3 times, it will create 3 threads with 3 labels on form with loop.
When I press the button once, it works fine. But when I press it more than once to create more labels, it runs into following problems:
As soon as button is pressed more than once, it stops the loop in previous thread and runs loop of new thread. If it is multithreaded then it should not stop first loop.
When loop of second label is finished, it gives following error
Object reference not set to an instance of an object
Here is my complete code. The line which throws error is at the end "mylabel[tcount].Text = i.ToString();".
Screenshot of program: https://i.sstatic.net/4MHOP.png
Screenshot of code https://i.sstatic.net/S0tQ0.png
namespace WindowsFormsApplication2{
public partial class Form1 : Form{
public Form1(){
InitializeComponent();
}
private int tcount = 0;
private int y_point = 0;
Thread[] threads = new Thread[5];
Label[] mylabel = new Label[5];
private void button1_Click(object sender, EventArgs e){
threads[tcount] = new Thread(new ThreadStart(work));
threads[tcount].Start();
}
private void work(){
if (this.InvokeRequired){
this.Invoke(new MethodInvoker(delegate{
mylabel[tcount] = new Label();
mylabel[tcount].Text = "label" + tcount;
mylabel[tcount].Location = new System.Drawing.Point(0, y_point + 15);
y_point += 25;
this.Controls.Add(mylabel[tcount]);
for (int i = 0; i < 10000; i++){
mylabel[tcount].Text = i.ToString();
Application.DoEvents();
}
}));
}
tcount++;
}
}
}
Upvotes: 3
Views: 1573
Reputation: 62157
If it is multithreaded then it should not stop first loop.
But it is not multithreaded.
this.Invoke(new MethodInvoker(delegate{
This switches via invoker the context back to the UI Thread, so while you open a lot of threads in the background, you basically then put all the processing back into one main thread.
This:
Application.DoEvents();
Then gives other queued work a chance. Still only on the UI thread.
And finally you never parametrize the threads so they all work on the same variables. There is only one non thread save (no lock, no volatile) variable named tCount - bang.
Basically you demonstrate:
Back to reading documentation I would say.
Upvotes: 9
Reputation: 23113
The problem is the scope of tcount
, as all threads acces the same instance of it, so as soon as the second thread starts the first thread also wirtes into the second label.
Also you invoke your whole worker method which will let it run in the UI-Thread again -> not actually multithreaded...
Your worker method should look something like this:
private void work()
{
int tIndex = tCount; //store the index of this thread
tcount++;
mylabel[tIndex] = new Label();
mylabel[tIndex].Text = "label" + tcount;
mylabel[tIndex].Location = new System.Drawing.Point(0, y_point + 15);
y_point += 25;
Invoke((MethodInvoker)delegate() { this.Controls.Add(mylabel[tIndex]); });
for (int i = 0; i < 10000; i++)
{
//doWork
Invoke((MethodInvoker)delegate() { mylabel[tIndex].Text = i.ToString(); });
}
}
Upvotes: 3
Reputation: 408
Jep, you need to copy tcount to a local variable. As soon as you hit the button twice while a thread has not yet terminated, it is manipulating the second one.
Upvotes: 0