Reputation: 11429
I'm having some trouble writing a function to change a background image on a div on document.ready
I haven't made a jsfiddle as i think the problem is just my poor (but improving) jQuery skills. Please let me know if you think one is needed.
Background Info -> I have a collection of div's with a class of portlet-visible or portlet-hidden, each of these div's will have another class of red-arrow (or a different color, but once i have one color it should be easy to extrapolate). When the page loads i would like a function that can find all divs with a class of portlet-hidden or portlet-visible and see if those have a class of red-arrow. If they do then change the background image src to a different value.
Im really struggling to work this one out, and any help is much appreciated.
My HTML
<div class="portlet-visible red-arrow"></div>
My CSS
div.portlet-visible
{
position:absolute;
top:12px;
right:10px;
background-image:url(../images/red-arrow-up.png);
width:14px;
height:14px;
}
And finally my javascript
$(document).ready(function() {
$(".portlet-hidden" && ".portlet-visible").each(function() {
if ($("this").hasClass(".red-arrow")) {
$(this).css(background-image, url('"url(../images/blue-arrow-up.png)"')
};
});
});
Upvotes: 0
Views: 471
Reputation: 69915
Multiple selectors should be separated by a comma(,
) and also css
method takes a string or a map. Try this.
$(document).ready(function() {
$(".portlet-hidden, .portlet-visible").each(function() {
if ($(this).hasClass("red-arrow")) {
$(this).css('background-image', "url('../images/blue-arrow-up.png')")
};
});
});
Upvotes: 3
Reputation: 11114
First... Archer's answer is spot on-- what you're trying to do with jQuery can be done with CSS alone.
But if for some reason you do need jQuery, a few things are wrong here.
First, as justtkt said in his answer, your selector is wrong. There is no need (and is syntactically wrong) to use conditional operators like && or || in a jQuery selector. This is simply because there is already conditional syntax built in to CSS, upon which jQuery selectors are directly based.
.this-class.that-class
Selects all elements with both .this-class
, and .that-class
.
#this-id.that-class
Is a very (possibly overly) specific declaration that select an element (there should only be one ID per page) with both #this-id and .that-class
For more on selectors, please read this very thorough, complete, and educational link http://www.w3.org/TR/selectors/
Additionally and importantly
This line:
$("this").hasClass(".red-arrow")
Is wrong! hasClass does not require a selector (the ".") because it only takes a class. It should be
$("this").hasClass("red-arrow")
Also!!
$(this).css(background-image, url('"url(../images/blue-arrow-up.png)"')
This line has some errors... should be:
$(this).css("background-image", "url(../images/blue-arrow-up.png)")
although I think the following syntax is easier:
css({'background-image' : 'url(../images/blue-arrow-up.png)'})
Upvotes: 1
Reputation: 26163
Unless there's a specific reason you want to do this with jQuery you should just use CSS...
div.portlet-visible
{
background-image:url(../images/red-arrow-up.png);
width:14px;
height:14px;
}
div.portlet-visible.red-arrow
{
background-image:url(../images/blue-arrow-up.png);
}
Any div with the class "portlet-visible" is defined in the first block, and any div with the classes "portlet-visible" and "red-arrow" will use the same css, but also apply the new background image.
http://jsfiddle.net/johncmolyneux/gcm5b/
Upvotes: 1
Reputation: 18588
".portlet-hidden,.portlet-visible"
boolean
from stringchange in css
.
$(".portlet-hidden,.portlet-visible").each(function(){
if ($("this").hasClass("red-arrow")){
$(this).css("background-image", "url('../images/blue-arrow-up.png')");
}
});
Upvotes: 0
Reputation: 114417
if ('$("this").hasClass(".red-arrow")') {
<--- this condition is a string here
Should be:
if ($(this).hasClass(".red-arrow")) {
Upvotes: 0
Reputation: 14776
Instead of &&
two selectors together, use the multiple selector like $(".portlet-hidden, .portlet-visible")
or the .add() method to build up your jQuery.
Your current line is actually anding the two strings together, which I believe will return boolean true in Javascript.
Upvotes: 0
Reputation: 413996
Your selector is just incorrect. If you want to match things with both classes, it'd be:
$('.portlet-hidden.portlet-visible').each( ...
If you want to match either of the classes:
$('.portlet-hidden, .portlet-visible').each( ...
The expression ".portlet-hidden" && ".portlet-visible"
will always evaluate to just ".portlet-visible"
.
Upvotes: 0
Reputation: 21840
I would have written the selector this way
$(".portlet-hidden, .portlet-visible")
Upvotes: 2