Reputation: 2223
Is it possible to run a .html or .exe for example, that is inside a zipfile? I'm using the Zipfile module.
Here's my sample code:
import zipfile
z = zipfile.ZipFile("c:\\test\\test.zip", "r")
x = ""
g = ""
for filename in z.namelist():
#print filename
y = len(filename)
x = str(filename)[y - 5:]
if x == ".html":
g = filename
f = z.open(g)
After f = z.open(g)
, I don't know what to do next. I tried using the .read()
but it only reads whats inside of the html, what I need is for it to run or execute.
Or is there any othere similar ways to do this?
Upvotes: 2
Views: 2081
Reputation: 414905
Run the first .html
file in a zip archive specified at the command line:
#!/usr/bin/env python
import os
import shutil
import sys
import tempfile
import webbrowser
import zipfile
from subprocess import check_call
from threading import Timer
with zipfile.ZipFile(sys.argv[1], 'r') as z:
# find the first html file in the archive
member = next(m for m in z.infolist() if m.filename.endswith('.html'))
# create temporary directory to extract the file to
tmpdir = tempfile.mkdtemp()
# remove tmpdir in 5 minutes
t = Timer(300, shutil.rmtree, args=[tmpdir], kwargs=dict(ignore_errors=True))
t.start()
# extract the file
z.extract(member, path=tmpdir)
filename = os.path.join(tmpdir, member.filename)
# run the file
if filename.endswith('.exe'):
check_call([filename]) # run as a program; wait it to complete
else: # open document using default browser
webbrowser.open_new_tab(filename) #NOTE: returns immediately
T:\> open-from-zip.py file.zip
As an alternative to webbrowser
you could use os.startfile(os.path.normpath(filename))
on Windows.
Upvotes: 1
Reputation: 6886
The best approach will be to extract the required file to the Windows temp directory and execute it. I have modified your original code to create a temp file and execute it:
import zipfile
import shutil
import os
z = zipfile.ZipFile("c:\\test\\test.zip", "r")
x = ""
g = ""
basename = ""
for filename in z.namelist():
print filename
y = len(filename)
x = str(filename)[y - 5:]
if x == ".html":
basename = os.path.basename(filename) #get the file name and extension from the return path
g = filename
print basename
break #found what was needed, no need to run the loop again
f = z.open(g)
temp = os.path.join(os.environ['temp'], basename) #create temp file name
tempfile = open(temp, "wb")
shutil.copyfileobj(f, tempfile) #copy unzipped file to Windows 'temp' folder
tempfile.close()
f.close()
os.system(temp) #run the file
Upvotes: 1