Reputation: 58953
I have a stored procedure with an IN OUT parameter declared like follows:
create or replace PROCEDURE RIFATT_SEGN0_INS(pIdRifattSegn0 in OUT NUMBER,
pNumDossier IN VARCHAR2 ,
pNumConsegna IN NUMBER,
pDtConsegna IN DATE,
[..]
) AS
[..]
Whenever i call it from another procedure, how do i get the pIdRifattSegn0 parameter that is also out?
Upvotes: 3
Views: 61301
Reputation: 132710
Your question isn't entirely clear. An IN OUT parameter is passed both ways, as its name implies. This means it has to be passed a variable, not a literal and you need a declare block to do that. For example:
declare
l_segn number;
begin
l_segn := 1;
-- procedure will have received value = 1
rifatt_segn0_ins(l_segn, 'x', 2, sysdate);
-- procedure may have changed value of l_segn from 1 to something else
dbms_output.put_line(l_segn);
end;
Upvotes: 14
Reputation: 17705
Here is an example:
SQL> create or replace PROCEDURE RIFATT_SEGN0_INS
2 ( pIdRifattSegn0 IN OUT NUMBER
3 , pNumDossier IN VARCHAR2
4 , pNumConsegna IN NUMBER
5 , pDtConsegna IN DATE
6 )
7 as
8 begin
9 dbms_output.put_line(pNumDossier);
10 dbms_output.put_line(to_char(pNumConsegna));
11 dbms_output.put_line(to_char(pDtConsegna,'yyyy-mm-dd'));
12 pIdRifattSegn0 := sqrt(pIdRifattSegn0);
13 end;
14 /
Procedure is aangemaakt.
SQL> create or replace procedure another_procedure
2 as
3 l_IdRifattSegn0 number := 4;
4 begin
5 rifatt_segn0_ins
6 ( pIdRifattSegn0 => l_IdRifattSegn0
7 , pNumDossier => '1A'
8 , pNumConsegna => 42
9 , pDtConsegna => sysdate
10 );
11 dbms_output.put_line('from another_procedure: l_IdRifattSegn0 = ' || to_char(l_IdRifattSegn0));
12 end;
13 /
Procedure is aangemaakt.
SQL> exec another_procedure
1A
42
2009-05-21
from another_procedure: l_IdRifattSegn0 = 2
PL/SQL-procedure is geslaagd.
Regards, Rob.
Upvotes: 2