CODEWITHSUNDEEP
c#stringchar
hafizhans
hafizhans

Reputation: 25

char to string error

I'm currently just 2 errors away from a working program. I'll post the line that contains error and the definition of its variable and finally the errors. Please tell me where i got wrong. Thank you.

    private Dictionary<string, bool[]> letterData = new Dictionary<string, bool[]>();


    public char[] mapNeurons()
    {
        char[] map = new char[this.letters.Items.Count];

        for (int i = 0; i < map.Length; i++)
        {
            map[i] = '?';
        }
        for (int i = 0; i < this.letters.Items.Count; i++)
        {
            double[] input = new double[Form1.DOWNSAMPLE_HEIGHT * Form1.DOWNSAMPLE_WIDTH];
            char ch = ((string)(this.letters.Items[i]))[0];
            bool[] data = this.letterData[ch]; //line contains errors
            for (int j = 0; j < input.Length; j++)
            {
                input[j] = data[j] ? 0.5 : -0.5;
            }

            int best = this.network.Winner(input);
            map[best] = ch;
        }
        return map;
    }

and here are the error

Error 1 The best overloaded method match for 'System.Collections.Generic.Dictionary.this[string]' has some invalid arguments

Error 2 Argument '1': cannot convert from 'char' to 'string'

I used Char instead of String because if using String it will return the whole line of the string loaded, i just wants to return the first letter of the string

for example: data = A1:000001100000000110000000111000000011100000001

if use string it will return the whole line, i just wants it to return 'A'

NEW IDENTIFIED PROBLEM: when i enter the data, i put the data into 'A1' key, which explain why im using string, so when it didnt find 'A1' because it is char, it just find 'A' thats why it returned '?', is it possible if i use string n just read the first character which is 'A' in the string line?

Upvotes: 1

Views: 4705

Answers (7)

Amar Palsapure
Amar Palsapure

Reputation: 9680

To convert char to string, ToString() can be called. This is the solution for the question.

But hafizhans, was working on some program, for which he had asked question, where he converted the Dictionary<char, bool[]> to Dictionary<string, bool[]>. Now he was storing the data from dictionary to text file something like this

A1:001110000111100001010100

Now while reading this, he only needed A1 part, so Split function did the trick. enter image description here

Upvotes: 1

joe_coolish
joe_coolish

Reputation: 7259

UPDATED

Try this:

if(this.letterData.ContainsKey(ch.ToString()))
    bool[] data = this.letterData[ch.ToString()];

or

if(this.letterData.ContainsKey(ch.ToString()))
    bool[] data = this.letterData[ch+""];

Upvotes: 1

jrummell
jrummell

Reputation: 43077

First of all, you need to add items to the dictionary with the Add() method.

Secondly, your dictionary's key is a string, so you need to use a string as the index ... you can get the string representation of a char by calling ToString() on the char instance.

char ch = 'x';

private Dictionary<string, bool[]> letterData = new Dictionary<string, bool[]>();
letterData.Add(ch.ToString(), new []{true, false});

bool[] data = this.letterData[ch.ToString()];

Or change the index to char:

char ch = 'x';

private Dictionary<char, bool[]> letterData = new Dictionary<char, bool[]>();
letterData.Add(ch, new []{true, false});

bool[] data = this.letterData[ch];

Upvotes: 4

competent_tech
competent_tech

Reputation: 44931

How about changing to:

string sCh = ch.ToString();
bool[] data = null;
if (this.letterDate.ContainsKey(sCh)
{
   data = this.letterData[sCh];
}

In addition, you may want consider changing the key on the dictionary to be Char instead.

Upvotes: 0

gabsferreira
gabsferreira

Reputation: 3137

bool[] data = this.letterData[ch.ToString()];

Upvotes: 2

MyKuLLSKI
MyKuLLSKI

Reputation: 5325

Try the following:

char charString = 'a';
if (letterData.ContainsKey(charString.ToString()))
{
    // Found
}

Upvotes: 0

thumbmunkeys
thumbmunkeys

Reputation: 20764

the variable ch is most likely a char you have to use a string instead

Upvotes: 0

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