Reputation: 1136
I have two arrays as shown below. I want to remove Array2 elements from Array1. How do I do that?(either in plain java script or using ExtJS)
var Array1 = [];
var Array2 = [];
Array1.push(['eth0'], ['eth1']);
Array2.push(['eth1']);
Upvotes: 0
Views: 727
Reputation: 338228
function removeDupes(a1, a2) {
var index = {}, result = [], i, l;
for (i=0, l=a2.length; i<l; i++) {
index['-' + a2[i]] = "";
}
for (i=0, l=a1.length; i<l; i++) {
if (index['-' + a1[i]] !== "") result.push(a1[i]);
}
return result;
}
index
object is for speedy look-up of values so we can test their existence quickly.'-' +
is to migrate the fact that values could be things like toString
that also exist as object properties. When prefixed with a letter that regular JavaScript identifiers cannot start with, every value will be safe for use as an object key. Example:
removeDupes([1,2,3,4], [2,4,5]);
// -> [1,3]
removeDupes([2,4,5], [1,2,3,4]);
// -> [5]
Upvotes: 1
Reputation: 6623
Check this link: http://www.developersnippets.com/2008/10/30/remove-duplicates-from-array-using-javascript/. Concat your arrays with concat() and call uniqueArr().
Upvotes: 0
Reputation: 5136
If you have the array filter function available to you, you can do something like the following:
var filteredArr = Array1.filter(function(val){
return Array2.indexOf(val) != -1;
})
I think this will only be supported in newer browsers, though. It's an elegant way to handle the situation, so you may want to take a look at a library like UnderscoreJS which will include filtering, defaulting to the native implementation if available.
If using UnderscoreJS, the code would look very similar:
var filterdArr = _.filter(Array1, function(val) {return Array2.indexOf(val) != -1});
Upvotes: 1