Reputation: 29
I've spent the last 2 hours trying to find a solution for this and came up with nothing. So either this is not possible or its so basic that no one write about this. Basically I have 2 strings that both equal numbers, but when I go to add them together I get a concatenate instead of a number.. here is my code (Python)
currentNukeScriptName = nuke.root().name()
splitUpScriptName1 = currentNukeScriptName.split('/')
splitUpScriptName2 = splitUpScriptName1[-1]
splitScriptNameAndExtention = splitUpScriptName2.split('.')
currentNukeScriptName = splitScriptNameAndExtention[0]
splitUpCurrentScriptName = currentNukeScriptName.split('_')
currentVersionNumber = splitUpCurrentScriptName[-1]
decimalVersionNumber = "1" + "," + str(currentVersionNumber)
addingNumber = 1
newVersionNumber = str(decimalVersionNumber) + str(addingNumber)
print newVersionNumber
decimaleVersionNumber = 1,019
If I change the newVersionNumber code too:
newVersionNumber = int(decimalVersionNumber) + int(addingNumber)
I get:
# Result: Traceback (most recent call last):
File "<string>", line 10, in <module>
ValueError: invalid literal for int() with base 10: '1,019'
I am unsure what to do.. Is this not possible? Or am I doing something totally wrong?
Edit:
So the problem was found in the decimalVersionNumber where I was adding a comma. What would be the best way of keeping the comma and still adding the numbers together?
Upvotes: 1
Views: 2663
Reputation: 1346
You need to use
int.Parse(decimalVersionNumber) + int.Parse(addingNumber)
This will parse the string representation of the numbers into integers, so they can be added.
eg:
String concatenation:
"10" + "20" = "1020"
Integer addition, parsed from strings:
int.Parse("10") + int.Parse("20") = 30
Upvotes: 0
Reputation: 16718
ValueError: invalid literal for int() with base 10: '1,019'
Sounds like it doesn't like the comma - try removing it first.
Upvotes: 6