CODEWITHSUNDEEP
sqljoindoctrine-ormdql
Russian Raccoon
Russian Raccoon

Reputation: 127

Doctrine 2 JOIN error

I try to execute this query

    $qb = $this->_em->createQueryBuilder();
    $qb->select(array('c', 'ld'))
            ->from('Model\Entity\Company', 'c')
            ->leftJoin('c.legaldetails', 'ld')
            ->where("c.companyid = 1");

    $query = $qb->getQuery();
    echo($query->getSQL());

having this sql code at the end:

SELECT ... FROM Company c0_ LEFT JOIN WHERE c0_.CompanyID = 1

These are my models:

<?php    
namespace Model\Entity;

use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
 * Company
 *
 * @ORM\Table(name="Company")
 * @ORM\Entity(repositoryClass="\Model\Repository\CompanyRepository")
 */
class Company
{
/**
 * @var integer $companyid
 *
 * @ORM\Column(name="CompanyID", type="integer", nullable=false)
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="IDENTITY")
 */
private $companyid;

/**
 * @var \Model\Entity\LegalDetails $legaldetails
 *
 * @ORM\OneToOne(targetEntity="\Model\Entity\Legaldetails", mappedBy="companyid")
 */
private $legaldetails;

//other fields

public function __construct()
{
    $this->legaldetails = new ArrayCollection();
}    

//setters and getters

and legaldetails entity:

<?php
namespace Model\Entity;

use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
 * Legaldetails
 *
 * @ORM\Table(name="LegalDetails")
 * @ORM\Entity
 */
class Legaldetails
{
/**
 * @var integer $legalid
 *
 * @ORM\Column(name="LegalID", type="integer", nullable=false)
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="IDENTITY")
 */
private $legalid;

/**
 * @var \Model\Entity\Company $company
 *
 * @ORM\Column(name="CompanyID", type="integer", nullable=false)
 * @ORM\OneToOne(targetEntity="\Model\Entity\Company", inversedBy="companyid")
 * @ORM\JoinColumn(name="companyid", referencedColumnName="companyid")
 */
private $company;

What is wrong?

P.S.: I understand that having two fields with identical names (companyid) is a bad practice, but it is not my fault

Upvotes: 2

Views: 1033

Answers (1)

Gangnus
Gangnus

Reputation: 24464

Judging on SQL operator, JOIN ON what? You missed the key part of join operator. Maybe, ON table.companyid=table2.companyid? Using the same names in tables could be even useful and is usual, not bad practice. You could put here the full SQL operator, that would be a better practice. :-)

Upvotes: 2

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